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Delicious77 [7]

3 years ago

9

Simplify the equation -4d - 37 = 7d + 18

2 answers:

allochka39001 [22]3 years ago

6 0

-4d - 37 = 7d + 18
-4x - 7d - 37 = 18
-11d - 37 = 18
+ 37 +37
-11d = 55
/-11 /-11
d = -5
So the answer is -5.

exis [7]3 years ago

5 0

Answer:

d=-5

Step-by-step explanation:

-4d-37=7d +18

move the terms to its correct side

-4d-7d=18+37

calculate the like terms together.

-11d=55

divide both sides by -11. both of the negavtive (-11) will cancel out and become d on the left and on the right 55 will be divided by -11 = -5. the 5 is negative because there's a negative -11 if there were a postive 11 it will be 5 instead of D=-5

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zhenek [66]

<em>Greetings from Brasil...</em>

First degree equation. The variables are in the 1st member and the numbers in the 2nd member.

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4 years ago

Select the correct answer. Which relationship does the graph represent?

vladimir2022 [97]

Answer:

D

Step-by-step explanation:

perimeter of square = 4 length of its sides

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8 0

2 years ago

Can someone help me out please, thank you.

Nutka1998 [239]

Here are a few rules about exponents you should know:

Multiplying exponents of the same base: $x^m*x^n=x^{m+n}$
Dividing exponents of the same base: $\frac{x^m}{x^n}=x^{m-n}$
Powering a power to a power: $(x^m)^n=x^{m*n}$
Converting a negative exponent into a positive one: $x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m$

Firstly, multiply the y bases: $\frac{z^5}{(-y^{-4}y^{-1}x^3)^{-3}}=\frac{z^5}{(-y^{-4+-1}x^3)^{-3}}=\frac{z^5}{(-y^{-5}x^3)^{-3}}$

Next, solve the power: $\frac{z^5}{(-y^{-5}x^3)^{-3}}=\frac{z^5}{-y^{-5*-3}x^{3*-3}}=\frac{z^5}{-y^{15}x^{-9}}$

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5 0

3 years ago

The equations of three lines are given below. Line 1: y = - 3/4 x + 3 Line 2/8 x - 6y = 2 Line 3/- 3y = 4x + 7 For each pair of

Maru [420]

Answer:

No parallel lines

Lines 1 and 3 are perpendicular

Step-by-step explanation:

Given:

$Line\ 1:y = -\frac{3}{4}x + 3$

$Line\ 2: \frac{2}{8}x -6y = 2$

$Line\ 3: 3y = 4x + 7$

Required

Determine if they are parallel, perpendicular or not

The slope intercept of a line has the form:

$y = mx + b$

Where

$m = slope$

First, we calculate the slope of each lines

$Line\ 1:y = -\frac{3}{4}x + 3$

Compare the above to $y = mx + b$

$m_1 = -\frac{3}{4}$

$Line\ 2: \frac{2}{8}x -6y = 2$

$\frac{2}{8}x -6y = 2$

Make -6y the subject

$-6y = 2 - \frac{2}{8}x$

Divide through by -6

$y = -\frac{2}{6} + \frac{2}{8*6}x$

$y = -\frac{1}{3} + \frac{1}{8*3}x$

$y = -\frac{1}{3} + \frac{1}{24}x$

$y = \frac{1}{24}x-\frac{1}{3}$

Compare the above to $y = mx + b$

$m_2 = \frac{1}{24}$

$Line\ 3: 3y = 4x + 7$

$3y = 4x + 7$

Divide through by 3

$y = \frac{4}{3}x + \frac{7}{3}$

Compare the above to $y = mx + b$

$m_3 = \frac{4}{3}$

So, we have:

$m_1 = -\frac{3}{4}$

$m_2 = \frac{1}{24}$

$m_3 = \frac{4}{3}$

None of the slopes are the same, so none of the lines are parallel.

However, lines 1 and 3 are perpendicular.

This is shown below

When the slope of two lines satisfy the following condition, then they are perpendicular.

$m_1 = -\frac{1}{m_3}$

This gives:

$-\frac{3}{4} = -\frac{1}{4/3}$

$-\frac{3}{4} = -1/\frac{4}{3}$

Convert / to *

$-\frac{3}{4} = -1*\frac{3}{4}$

$-\frac{3}{4} = -\frac{3}{4}$

3 0

3 years ago

Find the gradient of the line passing through (0,2) and (3,5)<br><br> pls i need for hwk

belka [17]

Answer:

The gradient is 1

Step-by-step explanation:

m, gradient= (y2-y1) ÷ (x2-x1)

8 0

2 years ago