Answer:
1/2 , no difference to the fraction of the sons
Explanation:
Since the disorder is inherited recessive gene on the X. The woman will be a carrier since her father had G6PD. Therefore her genotype is X Xh
The normal man genotype will be XY
The genotype of their offspring will be
- Daughters XX, XXh
- Sons XY, XhY
Therefore 1 out of the 2 sons(1/2) will have the disorder
If the father had the disorder, it will not change the fraction of the sons because the disorder is on the X chromosome. However one of the daughters will have it XhXh
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