Let the first term be a, 4th term be , difference between terms be d, and sum of first nine terms be
.
= a + 3d
32 = 11 + 3d
3d = 32 - 11
3d = 21
d = 7
=
=
= 9(11+28)
= 9(39)
= 325
Sum of first nine terms is 351.
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2 answers:
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Answer:
0.14% probability that the sample proportion exceeds 0.2
Step-by-step explanation:
I am going to use the binomial approximation to the normal to solve this question.
Binomial probability distribution
Probability of exactly x sucesses on n repeated trials, with p probability.
Can be approximated to a normal distribution, using the expected value and the standard deviation.
The expected value of the binomial distribution is:
The standard deviation of the binomial distribution is:
Normal probability distribution
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean and standard deviation
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
When we are approximating a binomial distribution to a normal one, we have that ,
.
In this problem, we have that:
So
What is the probability that the sample proportion exceeds 0.2
This is 1 subtracted by the pvalue of Z when X = 0.2*108 = 21.6. So
has a pvalue of 0.9986
1 - 0.9986 = 0.0014
0.14% probability that the sample proportion exceeds 0.2
Answer:
See the attachment
Step-by-step explanation:
It is convenient to use a spreadsheet or graphing calculator for this.
