Question

3x-8<=23 AND -4x+26>=6

Answer 1

Answer:

Step 1:  Solve for x in the first equation

$3x-8+8\leq 23+8$

$3x\leq 31$

$3x/3\leq 31/3$

$x\leq \frac{31}{3}$

Step 2:  Solve for x in the second equation

$-4x + 26-26 \geq 6-26$

$-4x\geq -20$

$-4x/-4\geq -20/-4$

Since you divide by a negative, you must flip the sign.

$x\leq 5$