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ratelena [41]
3 years ago
11

Help! need these answers filled in for school asap

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

Given : JKLM is a rectangle.

Prove: JL ≅ MK

Since, by the definition of rectangle all angles of rectangles are right angle.

Thus, In rectangle JKLM,

∠ JML and  ∠KLM are right angles.

⇒ ∠ JML ≅ ∠KLM

Since, JM ≅ KL   (Opposite sides of rectangles are congruent)

ML ≅ ML  ( Reflexive )

Thus, By SAS congruence postulate,

Δ JML ≅ Δ KLM

⇒ JL ≅ MK  ( because corresponding parts of congruent triangles are congruent)

Hence proved.

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Let f(x) = x2 − 2x − 3. The secant line through (2, f(2)) and (2 + h, f(2 + h)) for f(x) has slope h + 2. Use this formula to co
Mkey [24]

Answer:

a) slope of secant line = 3

b) slope of tangent line = 2

Step-by-step explanation:

Given:

- The function:

                           f(x) = x^2 -2*x - 3

- The slope for f(x) @ x = 2 is:

                           slope = h + 2

Find:

a) The slope of the secant line through (2, f(2)) and (3, f(3))

b) The slope of the tangent line at x = 2

Solution:

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- The slope of secant line between points ( 2 , f(2) ) and ( 3 , f(3) ) is:

                             slope = h + 2

Where,  h is the step size between two points. h = 3 - 2 = 1

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Hence, the slope of the secant is 3.

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Hence, the slope of the tangent is 2.

5 0
3 years ago
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