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ratelena [41]
3 years ago
11

Help! need these answers filled in for school asap

Mathematics
1 answer:
vampirchik [111]3 years ago
3 0

Answer:

Given : JKLM is a rectangle.

Prove: JL ≅ MK

Since, by the definition of rectangle all angles of rectangles are right angle.

Thus, In rectangle JKLM,

∠ JML and  ∠KLM are right angles.

⇒ ∠ JML ≅ ∠KLM

Since, JM ≅ KL   (Opposite sides of rectangles are congruent)

ML ≅ ML  ( Reflexive )

Thus, By SAS congruence postulate,

Δ JML ≅ Δ KLM

⇒ JL ≅ MK  ( because corresponding parts of congruent triangles are congruent)

Hence proved.

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Let's see what we're working on here 

\frac{1}{2}  - 2(m) =?
            ? = 0
Simplify this → \frac{1}{2}

\frac{1}2y} - 2(m) = ?

\frac{2(m)(2)}{2}

\frac{1 - 4(m)}{2} = ?

\frac{1 - 4(m)}{2} = 2

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 Subtract ( - )the number 1 from each of your sides on this part

4(m) = 1 
Multiply( ×) the number -1 to your sides for this part of the equation 

Therefore, the value of m is \frac{1}{4}
m =  \frac{1}{4}


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