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3 years ago

Consider the leading term of the polynomial function. What is the end behavior of the graph? 2x^7-8x^6-3x^5-3

Mathematics

1 answer:

jeyben [28]3 years ago

8 0

Answer:

$\lim_{x \to -\infty}y = -\infty\\ \lim_{x \to \infty}y = \infty$

Step-by-step explanation:

Due to the fact that the degree of the polynomial is odd, we know one end must go up and the other down. Because the leading coefficient is even, we know that as x approaches negative infinity, y approaches negative infinity as well. As x approaches positive infinity, y approaches positive infinity.

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According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are brown, 15% are yellow, 12% are re

Nataly [62]

Answer:

a) P(Y') = 0.850

b) P(O) + P(Y) = 0.380

c) 0.001728 = 0.002 to 3 d.p

d) 0.7744 = 0.774 to 3 d.p

e) 0.120

Step-by-step explanation:

Probability of brown M&M's = P(Br) = 0.12

Probability of yellow M&M's = P(Y) = 0.15

Probability of red M&M's = P(R) = 0.12

Probability of blue M&M's = P(Bl) = 0.23

Probability of orange M&M's = P(O) = 0.23

Probability of green M&M's = P(G) = 0.15

Total probability = 1

a) The probability that a randomly selected peanut M&M is not yellow = 1 - P(Y) = 1 - 0.15 = 0.85

b) The probability that a randomly selected peanut M&M is orange or yellow = P(O) + P(Y) = 0.23 + 0.15 = 0.38

c) The probability that three randomly selected peanut M&M's are all red = P(R) × P(R) × P(R) = 0.12 × 0.12 × 0.12 = 0.001728

d) If you randomly select two peanut M&M's, compute that probability that neither of them are red

This probability = P(R') × P(R')

P(R') = 1 - P(R) = 1 - 0.12 = 0.88

P(R') × P(R') = 0.88 × 0.88 = 0.7744

e) If you randomly select two peanut M&M's, compute that probability that at least one of them is red

This probability = [P(R) × P(R')] + [P(R) + P(R)] = (0.12 × 0.88) + (0.12 × 0.12) = 0.1056 + 0.0144 = 0.120

3 0

3 years ago

Which statement and reason best complete the proof ?

Liula [17]

Answer:

Option D

Step-by-step explanation:

Segment BD = Segment BD by reflexive property.

And that will also complete the congruence by AAS postulate.

4 0

3 years ago

Use polynomial long division to find the quotient and the remainder when 2x^3-3x^2-2x-1 is divided by x-3

Alexxx [7]

Answer:

quotient: 2x^2 +3x +7
remainder: 20

Step-by-step explanation:

See the attachment.

At each step, the value being subtracted from the dividend is the product of the quotient term and the divisor. The quotient term is found by dividing the highest-degree term of the dividend by the highest degree term of the divisor (x).

When the dividend has a degree that is less than the degree of the divisor, we call that value (20) the remainder.