Answer:
7 inches
Step-by-step explanation:
First you have to find the average height of each class.
4th Grade:
56, 47, 54, 51, 53, 58, 48, 54, 46, 53
Then you have add it all up and divide it by how many students there are.
56 + 47 + 54 + 51 + 53 + 58 + 48 + 54 + 46 + 53 = 520
520 ➗10= 52
Same process for the 7th Grade.
You end up getting 52 and 59. You then Subtract it to get the answer to the question.
52 - 59= 7 inches
You first must find the 18% of the fish population.
You multiply 500 by .18 . You are supposed to get 90.
90 is the 18% fish increase.
Then you just add 500 + 90 and you will get 590 fish that are now in the school.
Answer:
the mixed fraction 9 3/4 means there are 9 4/4 s and one 3/4all togather there are 39/4 divid this by 3/4 to find the no of shifts. 39/4 ÷(3/4)
=39/4. ×4/3=13
13shifts
Answer:
Your answer is 17.5
Step-by-step explanation:
Turn your fraction into a decimal
2/5 = 0.4
Next multiply my given answer by 0.4
17.5 x 0.4 = 7
Therefore 17.5 is your final answer
Answer:
P_max = 9.032 KN
Step-by-step explanation:
Given:
- Bar width and each side of bracket w = 70 mm
- Bar thickness and each side of bracket t = 20 mm
- Pin diameter d = 10 mm
- Average allowable bearing stress of (Bar and Bracket) T = 120 MPa
- Average allowable shear stress of pin S = 115 MPa
Find:
The maximum force P that the structure can support.
Solution:
- Bearing Stress in bar:
T = P / A
P = T*A
P = (120) * (0.07*0.02)
P = 168 KN
- Shear stress in pin:
S = P / A
P = S*A
P = (115)*pi*(0.01)^2 / 4
P = 9.032 KN
- Bearing Stress in each bracket:
T = P / 2*A
P = T*A*2
P = 2*(120) * (0.07*0.02)
P = 336 KN
- The maximum force P that this structure can support:
P_max = min (168 , 9.032 , 336)
P_max = 9.032 KN
