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3 years ago

Is 6x-2/5 equivalent to 6/5x - 2/5

Mathematics

1 answer:

lisabon 2012 [21]3 years ago

6 0

Expressions are said to be equivalent if they hold the same value.

$6x - \frac{2}{5}$ and $\frac{6}{5x} -\frac{2}{5}$ are not equivalent.

Given that:

$6x - \frac{2}{5}$

Take LCM

$6x - \frac{2}{5} = \frac{6 \times 5x -2}{5}$

By comparison:

$\frac{6 \times 5x -2}{5}$ is not equal to $\frac{6}{5x} -\frac{2}{5}$

i.e.

$\frac{6 \times 5x -2}{5} \ne \frac{6}{5x} -\frac{2}{5}$

Hence,

$6x - \frac{2}{5}$ and $\frac{6}{5x} -\frac{2}{5}$ are not equivalent.

Read more about equivalent expressions at:

brainly.com/question/15715866

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Write an equation (any form) for the quadratic graphed below. Y=

Licemer1 [7]

Answer:

y = -2x^2 - 4x - 1

Step-by-step explanation:

We can see that the graph passes through (-2, -1), (-1, 1) and (0, -1).

Let's solve

ax^2 + bx + c = y

a(-2)^2 + b(-2) + c = -1

4a - 2b + c = -1

a(-1)^2 + b(-1) + c = 1

a - b + c = 1

a0^2 + b0 + c = -1

c = -1

we got c = -1 so we input it into the other 2

4a - 2b - 1 = -1

4a - 2b = 0

2a - b = 0

2a = b

a - b - 1 = 1

a - b = 2

a = b + 2

Let's input b = 2a

a = 2a + 2

-a = 2

a = -2

b = 2a = 2*(-2) = -4

c = -1

y = -2x^2 - 4x - 1

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2 years ago

When testing the difference between two population means and the population variances are unknown and unequal, the degrees of fr

levacccp [35]

Answer: 34 degrees of freedom should be used to find the p-value of the test .

Step-by-step explanation:

Degrees of Freedom relates to the maximum number of independent values, that have independence to vary in the sample.

Given : When testing the difference between two population means and the population variances are unknown and unequal, the degrees of freedom are calculated as 34.7.

But degree of freedom must be an integer , so we find the greatest integer less than equal to the calculated degree of freedom.

i.e. [df]=[34.7]= 34

Thus , 34 degrees of freedom should be used to find the p-value of the test .

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3 years ago

The weight of laboratory grasshoppers follows a Normal distribution, with a mean of 90 grams and a standard deviation of 2 grams

JulsSmile [24]

Answer:

95.44% of the grasshoppers weigh between 86 grams and 94 grams.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Mean of 90 grams and a standard deviation of 2 grams.

This means that $\mu = 90, \sigma = 2$