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3 years ago

-4(4-3p) help me with this question

Mathematics

2 answers:

Katen [24]3 years ago

4 0

Answer:

given, -4(4-3p)=0

multiplying, -16+12 p=0

or, 12p=16

or, p=16/12

therefore the value of p is 4/3 is answer...

SSSSS [86.1K]3 years ago

3 0

Answer:

-16 + 12p

Step-by-step explanation:

1st we distribute :P

-4 * 4 = -16 we also have to multiply the other number with the variable

-4 * -3p = 12p since we have two negative symbols they become a positive number.

now we have -16 + 12p

High Hopes

Barrii

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2 years ago

If a coin is flipped 4 times what is the probability that a coin will land on heads 4 times

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3 years ago

5) In a certain supermarket, a sample of 60 customers who used a self-service checkout lane averaged 5.2 minutes of checkout tim

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Answer:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

$S_p=2.940$

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

$df=60+72-2=130$

$p_v =P(t_{130}$

Assuming a significance level of $\alpha=0.05$ we have that the p value is lower than this significance level so then we can conclude that the mean for checkout time is significantly less for people who use the self-service lane

Step-by-step explanation:

Data given

Our notation on this case :

$n_1 =60$ represent the sample size for people who used a self service

$n_2 =72$ represent the sample size for people who used a cashier

$\bar X_1 =5.2$ represent the sample mean for people who used a self service

$\bar X_2 =6.1$ represent the sample mean people who used a cashier

$s_1=3.1$ represent the sample standard deviation for people who used a self service

$s_2=2.8$ represent the sample standard deviation for people who used a cashier

Assumptions

When we have two independent samples from two normal distributions with equal variances we are assuming that

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

And t follows a t distribution with $n_1+n_2 -2$ degrees of freedom and the pooled variance $S^2_p$ is given by this formula:

$\S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

System of hypothesis

Null hypothesis: $\mu_1 \geq \mu_2$

Alternative hypothesis: $\mu_1 < \mu_2$

This system is equivalent to:

Null hypothesis: $\mu_1 - \mu_2 \geq 0$

Alternative hypothesis: $\mu_1 -\mu_2 < 0$

We can find the pooled variance:

$\S^2_p =\frac{(60-1)(3.1)^2 +(72 -1)(2.8)^2}{60 +72 -2}=8.643$

And the deviation would be just the square root of the variance:

$S_p=2.940$

The statistic is given by:

$t=\frac{(5.2 -6.1)-(0)}{2.940\sqrt{\frac{1}{60}+\frac{1}{72}}}=-1.751$

The degrees of freedom are given by:

$df=60+72-2=130$

And now we can calculate the p value with:

$p_v =P(t_{130}$

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3 years ago

Is the given value a solution of the inequality

dsp73

Answer:

35 <5m

35/5 < 5m/5

7 < m

m = 8,9,10,11,12,.......

a + 6 $\geq$ 9

a + 6 - 6 $\geq$ 9 -6

a $\geq$ 3

a = 3,4,5,6,7,......

8-g > 5

8 -g +g > 5 +g

8 > 5 +g

8 -5 > 5 -5 +g

3 > g

g =4,5,6,7,8.......

Step-by-step explanation:

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2 years ago