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Oksanka [162]
3 years ago
12

a line that passes through the point (–1, 3) has a slope of 2. find another point on the line. a. (–3, 2) b. (0, 5) c. (1, 5) d.

(1, 4)
Mathematics
1 answer:
Brilliant_brown [7]3 years ago
4 0
The\ slope-point\ form:y-y_1=m(x-x_1)\\--------------------\\m=2;\ (-1;\ 3)\to x_1=-1\ and\ y_1=3\\\\y-3=2(x-(-1))\\y-3=2(x+1)\\y-3=2x+2\ \ \ |add\ 3\ to\ both\ sides\\y=2x+5\\\\a)\ (-3;\ 2)\\L=2;\ R=2(-3)+5=-6+5=-1\\L\neq R\\\\b)\ (0;\ 5)\\L=5;\ R=2(0)+5=5\\L=R\\\\c)\ (1;\ 5)\\L=5;\ R=2\cdot1+5=2+5=7\\L\neq R\\\\d)\ (1;\ 4)\\L=4;\ R=2\cdot1+5=2+5=7\\L\neq R\\\\Answer:\boxed{b)\ (0;\ 5)}
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Answer with Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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3 years ago
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Step-by-step explanation:

Simplify the following:

(-36)/14 (-18) (-3)/6

Hint: | Express (-36)/14 (-18) (-3)/6 as a single fraction.

(-36)/14 (-18) (-3)/6 = (-36 (-18) (-3))/(14×6):

(-36 (-18) (-3))/(14×6)

Hint: | In (-36 (-18) (-3))/(14×6), divide -18 in the numerator by 6 in the denominator.

(-18)/6 = (6 (-3))/6 = -3:

(-36-3 (-3))/14

Hint: | In (-36 (-3) (-3))/14, the numbers -36 in the numerator and 14 in the denominator have gcd greater than one.

The gcd of -36 and 14 is 2, so (-36 (-3) (-3))/14 = ((2 (-18)) (-3) (-3))/(2×7) = 2/2×(-18 (-3) (-3))/7 = (-18 (-3) (-3))/7:

(-18 (-3) (-3))/7

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(54 (-3))/7

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54 (-3) = -162:

Answer:  (-162)/7

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