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Pepsi [2]
2 years ago
9

Thanks you to those who have been helping me with my math homework much appreciation have these points as gratitude!

Mathematics
2 answers:
joja [24]2 years ago
7 0

Answer:

No problem happy to help.

7nadin3 [17]2 years ago
4 0

Answer:

cool

Step-by-step explanation:

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The Problem is 8-9 please reply back and thx for your time
schepotkina [342]

Answer:

-1

Step-by-step explanation:

8+9=17

9+8=17

17-8=9

17-9=8

But, 8-9 is -1

4 0
2 years ago
Word problem: $32.95 for an adult ticket and $22.95 for a junior ticket. one day, the park collected $10,612 from a total of 360
seropon [69]

x + y = 360 \\ 32.95x + 22.95y = 10612
First, solve
x = 360 - y

Substitute that into equation
32.95(360 - y) + 22.95y = 10612 \\ 11862 - 32.95y + 22.95y = 10612 \\ 11862 - 10y = 10612 \\ 10y = 1250 \\ y = 125

Substitute y = 125 into
x = 360 - 125 \\ x = 235

There were 235 adult tickets and 125 junior tickets.

Hope this helps. - M
6 0
2 years ago
- 4/5g=-12 how to solve that
lorasvet [3.4K]

Answer:

-4/5g=-12

-4g=-12x5

-4g=-60

g=15

8 0
2 years ago
Which of the following pairs of equations are perpendicular
quester [9]

Answer:

were are the pairs?

7 0
2 years ago
I rlly need help with this :(
kobusy [5.1K]

Using the normal distribution, it is found that:

a) The pilot is at the 72th percentile.

b) 19.13% of pilots are unable to fly.

<h3>Normal Probability Distribution</h3>

The z-score of a measure X of a normally distributed variable with mean \mu and standard deviation \sigma is given by:

Z = \frac{X - \mu}{\sigma}

  • The z-score measures how many standard deviations the measure is above or below the mean.
  • Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.

The mean and the standard deviation are given, respectively, by:

\mu = 72.6, \sigma = 2.7.

Item a:

The percentile is the <u>p-value of Z when X = 74.2</u>, hence:

Z = \frac{X - \mu}{\sigma}

Z = \frac{74.2 - 72.6}{2.7}

Z = 0.59

Z = 0.59 has a p-value of 0.7224.

72th percentile.

Item b:

The proportion that is able to fly is the <u>p-value of Z when X = 78 subtracted by the p-value of Z when X = 70</u>, hence:

X = 78:

Z = \frac{X - \mu}{\sigma}

Z = \frac{78 - 72.6}{2.7}

Z = 2

Z = 2 has a p-value of 0.9772.

X = 70:

Z = \frac{X - \mu}{\sigma}

Z = \frac{70 - 72.6}{2.7}

Z = -0.96

Z = -0.96 has a p-value of 0.1685.

0.9772 - 0.1685 = 0.8087 = 80.87%.

Hence the percentage that is unable to fly is:

100 - 80.87 = 19.13%.

More can be learned about the normal distribution at brainly.com/question/4079902

#SPJ1

3 0
2 years ago
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