15. Greg and Alana went out to dinner. Their dinner bill came to $68.89.

Gerald notices that the bank of lockers outside his math classroom are numbered 511, 513, 515, ..., 575. Determine the number of

marysya [2.9K]

Answer:

33

Step-by-step explanation:

(575-511)/2 + 1 = 33

8 0

3 years ago

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During ski season,the owner of ski shop has determined that the number of customers in a day is greater then or equal to 50 more

Scilla [17]

The question is incomplete. Here is the complete question:

During ski season,the owner of ski shop has determined that the number of customers in a day is greater than or equal to 50 more then the temperature(Fahrenheit) . Write an inequality for the problem and determine the constraints on the variables.

Answer:

$N\geq T+50$

Step-by-step explanation:

Let the number of customers be 'N' and the temperature in Fahrenheit be 'T'.

Given:

Number of customers is related to temperature in Fahrenheit as:

Number of customers is greater than or equal to 50 more than the temperature in Fahrenheit. This means,

$N\geq T+50$

Now, since 'N' represents number of customers and number can never be a negative quantity. So, the only constraint for this inequality is that the number of customers must be greater than or equal to 0.

So, $N\geq 0$

4 0

4 years ago

Simplify (4x − 6) − (3x + 6).

antiseptic1488 [7]

the answer is the first one A

8 0

4 years ago

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NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.

Norma-Jean [14]

Answer:

<u>Arc Measure</u>: equal to the measure of its corresponding central angle.

<u>Formulas</u>

$\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)$

$\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2$

$\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}$

<h3><u>Question 39</u></h3>

Given:

r = 7 in
$\theta$ = 90°

Substitute the given values into the formulas:

Arc AB = 90°

$\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)$

<h3><u>Question 40</u></h3>

Given:

r = 6 ft
$\theta$ = 120°

Substitute the given values into the formulas:

Arc AB = 120°

$\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)$

<h3><u>Question 41</u></h3>

Given:

r = 12 cm
$\theta$ = 45°

Substitute the given values into the formulas:

Arc AB = 45°

$\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)$

$\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)$

8 0

2 years ago

The support of a wood table are in the shape of a right triangle. Find the third angle of the triangle of the measure of one of

Semenov [28]

<h3>The measure of third angle of triangle is 67 degrees</h3>

<em><u>Solution:</u></em>

Given that,

The support of a wood table are in the shape of a right triangle

Since it is a right angle, one of the angle must be $90^{\circ}$

The measure of one of the angles is 23 degrees

To find: third angle angle

We know that,

Sum of all angles in triangle equals 180 degrees

Therefore,

$90^{\circ} + 23^{\circ} + \text{ third angle } = 180^{\circ}\\\\ \text{ third angle } + 113 = 180\\\\ \text{ third angle } = 180 - 113\\\\ \text{ third angle } = 67^{\circ}$

Thus measure of third angle of triangle is 67 degrees

5 0

3 years ago