15. Greg and Alana went out to dinner. Their dinner bill came to $68.89.

Someone help I really need it.

NeX [460]

Answer:

c

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

The scatter plot below shows the number of online posts Evie makes per day and the time at which she makes them. Identify any cl

Bezzdna [24]

Answer:

Well, looking at the chart, there is a cluster of 3 dots at 10 A.M and 5 at 6 P.M and over. I hope that helped :)

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Help please <br><br> look at picture <br><br> supplementary angles

8_murik_8 [283]

Answer:

x=16

Step-by-step explanation:

....,...................

5 0

2 years ago

On a 40 question test students gain 6 points for each correct answer and lose 0.5 points on each incorrect answer. If everyone r

juin [17]

Answer:

$\text{r}=5.5\text{c}-20$

Step-by-step explanation:

GIVEN: On a $40$ question test students gain $6$ points for each correct answer and lose $0.5$ points on each incorrect answer. If everyone required to give an answer to each question.

TO FIND: the formulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c.

SOLUTION:

Total number of incorrect questions $=40-\text{c}$

Total marks deducted due to incorrect question $=(40-\text{c})\times0.5=20-0.5\text{c}$

Total correct questions $=\text{c}$

Total marks scored $=6\text{c}$

Total raw marks $\text{r}=\text{total marks gained}-\text{total marks deducted}$

$\text{r}=6\text{c}-(20-0.5\text{c})$

$\text{r}=5.5\text{c}-20$

ormulas that describes how a student's raw score, r, depends on the number of correct answers he or she provided, c is $\text{r}=5.5\text{c}-20$

7 0

3 years ago

A dairy farm uses the somatic cell count (SCC) report on the milk it provides to a processor as one way to monitor the health of

Eva8 [605]

Answer:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

Step-by-step explanation:

Data given and notation

$\bar X=250000$ represent the sample mean

$s=37500$ represent the standard deviation for the sample

$n=5$ sample size

$\mu_o =210250$ represent the value that we want to test

$\alpha=0.1$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses to be tested

We need to conduct a hypothesis in order to determine if the mean is higher than 210250, the system of hypothesis would be:

Null hypothesis: $\mu \leq 210250$

Alternative hypothesis: $\mu > 210250$

Compute the test statistic

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

We can replace in formula (1) the info given like this:

$t=\frac{25000-210000}{\frac{37500}{\sqrt{5}}}=2.37$

Now we need to find the degrees of freedom for the t distirbution given by:

$df=n-1=5-1=4$

Conclusion

Since is a one right tailed test the p value would be:

$p_v =P(t_{4}>2.37)=0.038$

If we compare the p value and a significance level assumed $\alpha=0.1$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the actual true mean is higher than 210250 at 5% of significance.

6 0

3 years ago