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Anettt [7]
3 years ago
6

A population of 1200 leopards decreases by 12% per year. How many leopards will there be in the population after 6 years? Round

your answer to the nearest whole number
Mathematics
1 answer:
frez [133]3 years ago
3 0
12% of 1200 is 144, so subtract that. you get 1056. 12% of that is 126.72, so you subtract that. you get 929.28. 12% of that is 111.5136 and you subtract that. and so on and so forth. the answer would be 557.
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Go step by step to reduce the radical. <br> The square root of 96
lakkis [162]

Answer:

Step-by-step explanation:

We want to reduce the radical. In order to do that, we want to find the factors of 96 that are square numbers

The factors of 96 are:

1, 96, 2, 48, 3, 32, 4, 24, 6, 16...

16 is a square number, so we can rewrite

\sqrt{96} = \sqrt{16*6}  = \sqrt{16} * \sqrt{6}  = 4\sqrt{6}

5 0
2 years ago
Why is 3/4 greater thab 11/16 how can i be sure
Delicious77 [7]
You can make them have the same denominator and then compare

( \frac{3}{4}) ( \frac{16}{16}) =  \frac{48}{64}

(\frac{11}{16})( \frac{4}{4}) =  \frac{44}{64}

so as you can see, \frac{3}{4} is \frac{4}{64} bigger than  \frac{11}{16}
5 0
3 years ago
[{(-72)÷(-2)}2-(-7)]x(-10)
mote1985 [20]

Answer:

-790

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Gabbys age is two times mikhails age.the sum of their ages is 75. What is mikhails age
Tatiana [17]

Answer:

Mikhail's age is 25 years old

Step-by-step explanation:

Let's make an equation: Say Mikhail is x, so Gabby would be 2*x=2x

If the sum of their ages equals 75, then x+2x=75, and x=2x=3x, so 3x=75.

75/3=25

6 0
3 years ago
Suppose we are interested in analyzing the weights of NFL players. We know that on average, NFL players weigh 247 pounds with a
tigry1 [53]

Answer:

SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58

ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073

\bar X - ME = 237- 14.073 = 222.927

\bar X + ME = 237+ 14.073 = 251.073

n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238

So the answer for this case would be n=238 rounded up to the nearest integer

Null hypothesis:\mu \geq 247  

Alternative hypothesis:\mu  

z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165  

p_v =P(z  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

Step-by-step explanation:

For this case we have the following data given:

\bar X =237 represent the sample mean

\sigma = 47 represent the population deviation

n =30 represent the sample size selected

\mu_0 = 247 represent the value that we want to test.

The standard error for this case is given by:

SE= \frac{\sigma}{\sqrt{n}} = \frac{47}{\sqrt{30}}= 8.58

For the 90% confidence the value of the significance is given by \alpha=1-0.9 = 0.1 and \alpha/2 = 0.05 so we can find in the normal standard distribution a quantile that accumulates 0.05 of the area on each tail and we got:

z_{\alpha/2}= 1.64

And the margin of error would be:

ME= 1.64 *\frac{\sigma}{\sqrt{n}} = 1.64*\frac{47}{\sqrt{30}}= 14.073

The confidence interval for this case would be given by:

\bar X - ME = 237- 14.073 = 222.927

\bar X + ME = 237+ 14.073 = 251.073

The margin of error is given by this formula:

ME=z_{\alpha/2}\frac{\sigma}{\sqrt{n}}    (a)

And on this case we have that ME =5 and we are interested in order to find the value of n, if we solve n from equation (a) we got:

n=(\frac{z_{\alpha/2} \sigma}{ME})^2   (b)

Replacing into formula (b) we got:

n=(\frac{1.640(47)}{5})^2 =237.65 \approx 238

So the answer for this case would be n=238 rounded up to the nearest integer

State the null and alternative hypotheses.  

We need to conduct a hypothesis in order to check if the true mean is lower than 247 pounds, the system of hypothesis would be:  

Null hypothesis:\mu \geq 247  

Alternative hypothesis:\mu  

Since we know the population deviation, is better apply a z test to compare the actual mean to the reference value, and the statistic is given by:  

z=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)  

z-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic  

We can replace in formula (1) the info given like this:  

z=\frac{237-247}{\frac{47}{\sqrt{30}}}=-1.165  

P-value  

Since is a left tailed test the p value would be:  

p_v =P(z  

Conclusion  

If we compare the p value and the significance level given \alpha=0.1 we see that p_v>\alpha so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can't conclude that the true mean is lower than 247 at 10% of significance.

5 0
3 years ago
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