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Lostsunrise [7]
4 years ago
11

a tip jar contains 48 coins, all nickels, dimes, and quarters. the total value of the coins in 5.40. if thr value of the dimes i

s 55 cents less than the value of the nickels how many of each coin is in the jar ?
Mathematics
1 answer:
Butoxors [25]4 years ago
3 0

Answer:

number of nickle coins = 20

number of dime coins = 11

number of quarter coins = 17

Step-by-step explanation:

Worth of coins in one dollar : 1 quarter = 25% , 1 dime = 10%, 1 nickle = 5%

Now, let number of nickle coins be x and number of quarter coins be y

Number of dimes = 55% less than number of nickle

⇒ Number of dimes = 0.55·x

Now, according to question, Total number of coins in the jar = 48

⇒ x + 0.55·x + y = 48

⇒ 1.55·x + y = 48.........(1)

Total value of coins in the jar = 5.40

⇒ 0.05·x + 0.01 × 0.55·x + 0.25·y = 5.40

⇒ 0.0555·x + 0.25·y = 5.40

⇒ 5.55·x + 25·y = 540..........(2)

On solving (1) and (2), We get

x = 19.88 ≈ 20

y = 17.19 ≈ 17

Hence, number of nickle coins = 20

number of dime coins = 11

number of quarter coins = 17

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