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3 years ago

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Billy is constructing a garden divided into 8 equal sections. The diameter of the garden is 12 feet. What is the area, in square

feet, of one section of the garden?

1 answer:

pishuonlain [190]3 years ago

6 0

If the diameter of the garden is 12 ft, then the radius is 6 ft.

The area is then π(6 ft)^2, or 36 ft^2.

Then the area of one of the 8 equal sections of the garden is 36/8 ft^2, or 9/2 ft^2, or 4.5 ft^2.

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kykrilka [37]

Answer:

$K$ is equidistant from $H$ and $J$ .

Step-by-step explanation:

Given that the point $K$ which is on the perpendicular bisector of the line segment having endpoints at $H$ and $J$ .

The given situation can be represented as the diagram as attached in the answer area.

Referring to the $\triangle HOK, \triangle JOK$ :

$\angle HOK = \angle JOK=90^\circ$ (As it is the perpendicular bisector)

$OH = OJ$ (As it is the perpendicular bisector)

Also, the side $OK$ is the common side.

Therefore by $S-A-S$ congruence, $\triangle HKO\cong \triangle JKO$

As per the properties of congruent triangles:

Side $HK$ = Side $JK$

$HK$ and $JK$ are nothing but the distance of the point $K$ from the end points $H$ and $J$ which are proved to be equal to each other.

Therefore, we can conclude that:

$K$ is equidistant from $H$ and $J$ .

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3 years ago

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galben [10]

Answer:

y intercept: (0,4)

Step-by-step explanation:

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horsena [70]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

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4 years ago

Find the ninth term of the

pantera1 [17]

Answer:

$a_{9}$ =0.00015241579

Step-by-step explanation:

Use the formula for geometric sequences:

$a_{n}$ = $a_{1}$ $r^{n-1}$

Substitute 1 in for $a_{1}$ , -1/3 in for r, and 9 in for n

$a_{9}$ =(1)(-1/3^9-1)

$a_{9}$ =(1)(-1/3^8)

$a_{9}$ =(1)(0.00015241579)

$a_{9}$ =0.00015241579

Hope this helps! :)

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3 years ago