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4 years ago

I need help on 11-16

Mathematics

1 answer:

alisha [4.7K]4 years ago

6 0

I cant see all of 11 and 14
12:
$3f = 18 \\ \frac{3f}{3} = \frac{18}{3} \\ f = 6$
13:
$3f = {3}^{2} \\ 3f = 9 \\ \frac{3f}{3} = \frac{9}{3} \\ f = 3$
15:
$3h = 9 + 10 \\ 3h = 19 \\ \frac{3h}{3} = \frac{19}{3} \\ h = 6.3$
16:
$3f = 27 - 21 \\ 3f = 6 \\ \frac{3f}{3} = \frac{6}{3} \\ f = 2$

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Cot(x)=-3. find sin(x)

ASHA 777 [7]

Answer:

sin(x)=1/ $\sqrt10$

Step-by-step explanation:

The trigonometric identities involve trigonometric functions. Here we will be using Trigonometric identity

sin²x = 1 /( 1+cot²x )

now cot(x)= -3

⇒ cot²x= (-3)²

⇒ cot²x= 9

sin²x= 1/( 1+9)

⇒ sin²x = 1/10

taking under root on both the sides we get

√sin²x= $\sqrt1$ / $\sqrt10$

⇒ sin(x)=± 1/ $\sqrt10$

6 0

3 years ago

If logx27 + logy4 =5<br>and logx27 - logy4 =1<br>find x and y

Elanso [62]

Answer:

Hello,

I have reply too quick in comments (sorry)

Step-by-step explanation:

$\left\{\begin{array}{ccc}log_x (27)+log_y (4)=5\\log_x (27)-log_y (4)=1\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}2*log_x (27)=6\\2*log_y (4)=4\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}log_x (27)=3\\log_y (4)=2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x^{log_x (27)}=x^3\\y^{log_y (4)}=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}27=x^3\\4=y^2\\\end{array}\right.\\\\\\\left\{\begin{array}{ccc}x=3\\y=2\\\end{array}\right.\\\\$

5 0

3 years ago

What is the slope of a line that is parallel to the line represented by the equation y=7/6x+4

Alekssandra [29.7K]

7/6
The slope of the equation in the form y=Mx+c is m
Parallel lines have Same gradient
Which makes gradient 7/6

Please mark as brainliest

4 0

3 years ago

Rezolvati 1) -2x+1= -7 2) 6+3x= -54+x 3) 2x+9= 7 +x 4) 3-2x= -x -6 5) -3(x+1) = -6 6) -4 (x -2)=12 7) -7(x-3)= -14

Natalija [7]

<span>Răspunsurile sunt

1. x= 4
2. x = -30
3. x = -2
4. x = 9
5. x = 1
6. x = -1
7. x = 5
</span>

3 0

3 years ago

A random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard

azamat

Answer:

Option C

Step-by-step explanation:

Given that for a random sample of 20 houses selected from a city showed that the mean size of these houses is 1880 square feet with a standard deviation of 320 square feet.

X, the sizes of houses is Normal

Hence sample mean will be normal with

Mean = 1880

and std dev = $\frac{320}{\sqrt{20} } \\=71.5542$

For 90% confidence interval critical value for t with degree of freedom 19 is

1.328

Confidence interval upper bound

= mean + margin of error

= $1880+1.328*71.55\\=1975$

Option C is right

3 0

3 years ago