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ValentinkaMS [17]
3 years ago
6

A box contains 2 red marbles , 3 green marbles , and 3 blue marbles

Mathematics
1 answer:
krek1111 [17]3 years ago
5 0

Answer:

the box contains a total of 8 marbles .

although if you understand pixels then you would know that could stand for RGB so your color would be a very dark greenish brown

Step-by-step explanation:

no question?

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Mary wants to find this product. 58 x 20 How can Mary find the product? A. 0 +16 + 100 B. 0 + 160 + 1000 . C. 58 + 16 + 100 D. 5
Fittoniya [83]

Answer:

B

Step-by-step explanation:

58×20=1160

0+160+1000=1160

8 0
3 years ago
What set of reflections would carry triangle ABC onto itslelf?
riadik2000 [5.3K]
<h3>Answer: Choice A</h3>

y axis, x axis, y axis, x axis

============================

Explanation:

Reflecting an object over the y axis twice will have it end up in its starting position. The same can be said for the x axis as well. It doesn't matter that the x axis reflections aren't grouped next to each other, nor the y. So in a sense, two x axis reflections undo each other, so do the y axis reflections, and we end up with the same image as shown in the diagram.

6 0
3 years ago
List 3 values that would make this inequality true for 7 + x &lt; 13
Blizzard [7]
Three values that would make this true:

5
4
3
8 0
2 years ago
Graph the line with slope 1/2 passing through the point (-4,4).
Yakvenalex [24]

Answer:

Step-by-step explanation:

------------

It's a straight line, so you need 1 additional point.

---

Plot (-4,4)

Slope 1/2 --> y increases 2 for each 1 of x increase.

Add 1 to x, and 2 to y ---> (-3,6)

4 0
3 years ago
Find the next 3 terms in the geometric sequence -36, 6, -1, 1/6, ...
timama [110]

we are given

geometric sequence -36, 6, -1, 1/6, ...

first term is -36

a_1=-36

now, we can find common ratio

r=\frac{6}{-36}

r=-\frac{1}{6}

now, we can find nth term

a_n=a_1(r)^{n-1}

now, we can plug values

and we get

a_n=36(-\frac{1}{6})^{n-1}

now, we can find 5th term , 6th term, 7th term

fifth term:

a_5=36(-\frac{1}{6})^{4}

a_5=\frac{1}{36}

sixth term:

a_6=36(-\frac{1}{6})^{5}

a_6=-\frac{1}{216}

seventh term:

a_7=36(-\frac{1}{6})^{6}

a_7=\frac{1}{1296}

so, next terms are

a_5=\frac{1}{36} , a_6=-\frac{1}{216}

, a_7=\frac{1}{1296}.............Answer

6 0
3 years ago
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