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3 years ago

What is the length of LJ? the choices are 23.0 17.0 4.7 3.5

Mathematics

1 answer:

tatiyna3 years ago

7 0

4.7

It just is.....
It is what it is.....

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12. Match the function with the correct parabola.

Mekhanik [1.2K]

Step-by-step explanation:

a x^2/4

b -x^2/4+3

c 4x^2

d -x^2

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3 years ago

Two side length of a triangle are given as 9 cm and 5 cm. What could be the length of its third side?

astraxan [27]

Answer: Two sides are given 5 cm and 9 cm. .Therefore, the third side can not be greater than or equal to (9+5)=14 cm and it can not be less than or equal to (9–5)=4 cm

Step-by-step explanation:

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3 years ago

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Writing an Equation in Slope-Intercept Form

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Step-by-step explanation:

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3 years ago

Alvin’s age is two times Elga’s age. The sum of their age is 60. What is Elga’s age?

Nady [450]

x = Elgas age

2x = Alvins age

x +2x = 60

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Elga is 20 years old

4 0

4 years ago

If α and β are the zeros of the quadratic polynomial f(x) = 3x2–4x + 5, find a polynomialwhose zeros are 2α + 3β and 3α + 2β.

Lelechka [254]

Answer:

$\boxed{\sf \ \ \ 3x^2-20x+37\ \ \ }$

Step-by-step explanation:

Hello,

a and b are the zeros, we can say that

$f(x)=3(x^2-\dfrac{4}{3}x+\dfrac{5}{3}) = 3(x-a)(x-b)=3(x-(a+b)x+ab)$

So we can say that

$a+b=\dfrac{4}{3}\\ab=\dfrac{5}{3}$

Now, we are looking for a polynomial where zeros are 2a+3b and 3a+2b

for instance we can write

$(x-2a-3b)(x-3a-2b)=x^2-(2a+3b+3a+2b)x+(2a+3b)(3a+2b)\\= x^2-5(a+b)x+6a^2+6b^2+9ab+4ab$

and we can notice that

$a^2+b^2=(a+b)^2-2ab$ so

$(x-2a-3b)(x-3a-2b)=x^2-5(a+b)x+6[(a+b)2-2ab]+13ab\\= x^2-5(a+b)x+6(a+b)^2+ab$

it comes

$x^2-5*\dfrac{4}{3}x+6(\dfrac{4}{3})^2+\dfrac{5}{3}$

multiply by 3

$3x^2-20x+2*16+5=3x^2-20x+37$

4 0

3 years ago