Answer:
x=3,y=0
x=-1,y=0
Step-by-step explanation:
We will have to factorise to get the value of x before solving for y
Let's solve
y=x^2-2x-3
To factorise x
x^2-3x+x-3
x(x-3)+1(x-3)
(x-3)+(x+1)
x-3=0
x=3
x+1=0
x=-1
Let's substitute the value of value to get the value for y
y=x^2-2x-3
When x is 3
y=3^2-2(3)-3
y=9-6-3
y=0
When x is-1
y=(-1)^2-2(-1)-3
y=1+2-3
y=0
Therefore when x is 3,y is 0
When x is -1,y is 0
Answer:
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Answer:
f(9/2) = 17/2
Step-by-step explanation:
f(x) = 3x-5
let x=9/2
f(9/2) = 3*9/2 -5
f(9/2) = 27/2 - 5
get a common denominator
f(9/2) = 27/2 - 10/2
f(9/2) = 17/2
Answer:
L'(4, -4)
Step-by-step explanation:
When you're given a midpoint, you can find the point equidistant on the other side of the midpoint by subtracting the relevant coordinate from <em>double that of the midpoint</em>.
Here, the line of reflection is the horizontal line y=-1, so you know only the y-coordinate will change. The reflected point will be ...
(x, y) ⇒ (x, -2-y)
so the point of interest is ...
L' = (4, -2-2) = (4, -4)
Answer:

Step-by-step explanation:
By definition, tangent lines touch a circle at one point. This one point intersects the circle at a 90 degree angle.
In any circle, the measure of an inscribed angle is exactly half of the arc it forms. Since
forms an arc labelled 244 degrees, the measure of angle 2 must be
.
Angle 1 and 2 form one side of a line. Since there are 180 degrees on each side of the line, we have:
