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Mashcka [7]
3 years ago
14

Using an independent-measures t, the 90% confidence interval for the difference between two population means ranges from 19 to 2

3. Based on this confidence interval, you can conclude that the difference between the two sample means is ____.a) 4 pointsb) 19 pointsc) 21 pointsd) 23 points
Mathematics
2 answers:
Evgen [1.6K]3 years ago
7 0

Answer:

b

Step-by-step explanation:

We must determine the the x value at 90% confidence interval. We find this from a table relating confidence intervals and x values. For 90%, z is 1.645.

WE must determine the mean of 19 and 23:

=(19+23)/2=21

We must determine the standard deviation. We let n be the number of population which is 2. We need to take the numbers 19 and 23 and subtract  each by the mean and square the answer:

(19-2)^2=289

(23-2)^2=441

We then determine the mean of these two values as:

(289+441)/2=365

Now we take the square root of 365:

\sqrt{365}=19.1

The standard deviation is 19.1

The answer is b

DENIUS [597]3 years ago
7 0

Answer:

b

Step-by-step explanation:

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PLZ HELP QUICK-------------->
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<h2>>>> Answer <<<</h2>

Let's check which polynomial is divisible by ( x - 1 ) using hit , trial and error method .

A ( x ) = 3x³ + 2x² - x

The word " divisible " itself says that " it is a factor "

Using factor theorem ;

Let;

=> x - 1 = 0

=> x = 1

Substitute the value of x in p ( x )

p ( 1 ) =

3 ( 1 )³ + 2 ( 1 )² - 1

3 ( 1 ) + 2 ( 1 ) - 1

3 + 2 - 1

5 - 1

4

This implies ;

A ( x ) is not divisible by ( x - 1 )

Similarly,

B ( x ) = 5x³ - 4x² - x

B ( 1 ) =

5 ( 1 )³ - 4 ( 1 )² - 1

5 ( 1 ) - 4 ( 1 ) - 1

5 - 4 - 1

5 - 5

0

This implies ;

B ( x ) is divisible by ( x - 1 )

Similarly,

C ( x ) = 2x³ - 3x² + 2x - 1

C ( 1 ) =

2 ( 1 )³ - 3 ( 1 )² + 2 ( 1 ) - 1

2 ( 1 ) - 3 ( 1 ) + 2 - 1

2 - 3 + 2 - 1

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0

This implies ;

C ( x ) is divisible by ( x - 1 )

Similarly,

D ( x ) = x³ + 2x² + 3x + 2

D ( 1 ) =

( 1 )³ + 2 ( 1 )² + 3 ( 1 ) + 2

1 + 2 + 3 + 2

8

This implies ;

D ( x ) is not divisible by ( x - 1 )

<h2>Therefore ; </h2>

<h3>B ( x ) & C ( x ) are divisible by ( x - 1 ) </h3>
6 0
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