Ask question

Ask question

All categories

3 years ago

13

Help help urgentlyyy please❤️❤️

1 answer:

Julli [10]3 years ago

4 0

Answer:

g(2) = 5

g(-2) = 2

g(-3) = 0

g(5) = 1

g(x) = 0 when x = 3

g(x) = 6 when x = 0

Step-by-step explanation:

Your just finding the values of y when x is unknown or when y is unknown and your trying to find x. f(x) is just a fancy way of saying y.

You might be interested in

Is 7.8 greater than 7.800

blsea [12.9K]

Answer:

NO

Step-by-step explanation:

3 0

3 years ago

Given: circle k(O), m LM = 164°, m WK = 68°, m∠MLK = 65°. Find: m∠LMW

Musya8 [376]

Answer:

The measure of angle LMW is $m\angle LMW=67\°$

Step-by-step explanation:

see the attached figure to better understand the problem

step 1

Find the measure of arc MW

we know that

The inscribed angle measures half that of the arc comprising

so

$m\angle MLK=\frac{1}{2}[arc\ MW+arc\ WK]$

substitute the given values

$65\°=\frac{1}{2}[arc\ MW+68\°]$

$130\°=[arc\ MW+68\°]$

$arc\ MW=130\°-68\°=62\°$

step 2

Find the measure of arc LK

we know that

$arc\ LM+arc\ MW+arc\ WK+arc\ LK=360\°$ -----> by complete circle

substitute the given values

$164\°+62\°+68\°+arc\ LK=360\°$

$294\°+arc\ LK=360\°$

$arc\ LK=360\°-294\°=66\°$

step 3

Find the measure of angle LMW

we know that

The inscribed angle measures half that of the arc comprising

so

$m\angle LMW=\frac{1}{2}[arc\ LK+arc\ WK]$

substitute the given values

$m\angle LMW=\frac{1}{2}[66\°+68\°]=67\°$

4 0

3 years ago

F(x)= -2x + 2; Find f(5)

zhuklara [117]

If f(x) = -2x + 2, f(5) can be found by substituting in the value 5 for x in the equation:

f(5) = - 2(5) + 2

Our first step in simplifying this expression is to perform the multiplication as outlined by the order of operations (PEMDAS).

f(5) = -10 + 2

Finally, we must get our final answer by adding together the remaining terms.

f(5) = -8

Hope this helps!

7 0

4 years ago

One less than three times a number is two less than three times the number

AysviL [449]

$3x-1=3x-2\\
-1=-2\\
x\in \emptyset$

7 0

4 years ago

Pleaseeee help meeeee<br><br><br>What is ∑n=125(3n−2) equal to?

vichka [17]

Answer:

$\sum_{n=1}^{25}(3n-2)=925]$

Step-by-step explanation:

The given series is $\sum_{n=1}^{25}(3n-2)$

The first term of this series is

$a_1=3(1)-2$

$a_1=3-2$

$a_1=1$

The second term is

$a_2=3(2)-2$

$a_2=6-2$

$a_2=4$

The common difference is

$d=4-1=3$

The sum of the first n-terms is given by;

$S_n=\frac{n}{2}[2a_1+d(n-1)]$

The sum of the first 25 terms of the series is

$S_{25}=\frac{25}{2}[2(1)+3(25-1)]$

$S_{25}=\frac{25}{2}[2+3(24)]$

$S_{25}=\frac{25}{2}(74)]$

$S_{25}=925]$

4 0

4 years ago

Read 2 more answers