Answer: the rate of the canoeist in calm water is 6 mph and the rate of the current is 4 mph
Step-by-step explanation:
Let x represent the rate of the canoeist in calm water.
Let y represent the rate of the current.
The canoeist travels 30 miles downstream in three hours.. Assuming that he travelled in the direction of the current, his total speed would be x + y mph
Distance = speed × time
Distance covered downstream is
30 = 3(x + y)
10 = x + y - - - - - - - - - - - -1
Against the current the return trip took fifteen hours..
His total speed would be x - y mph
Distance = speed × time
Distance covered on return trip is
30 = 15(x - y)
2 = x - y - - - - - - - - - - - -2
Adding equation 1 and equation 2, it becomes
12 = 2x
x = 12/2 = 6 mph
Substituting x = 6 into equation 1, it becomes
10 = 6 + y
y = 10 - 6 = 4 mph
Answer:
6km
Step-by-step explanation:
Area of circle = πr²
Where r = radius, π= 3.14, A = 28.26km²
A = 3.14 x r²
3.14 r2 = 28.26
Divide both sides by 3.14
r²= 28.26/3.14
r² = 9
Square root both sides
r= √9
r= 3
Radius = 3km
Note : Diameter = 2 x radius
Diameter = 3 x 2
Diameter = 6km
I hope this was helpful, Please mark as brainliest.
Answer:
D. 5(x^2+5)
Step-by-step explanation:
5x^2+25
Viewing the two terms 5 is divisible by both
5X^2/5 +25/5
X^2+5
Therefore the equation will be represented by
5(x^2+5)
Answer:
Im pretty sure r = 1.49
Step-by-step explanation: