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Alex17521 [72]
2 years ago
10

12. Dua garis sejajar dipotong oleh sebuah garis

Mathematics
1 answer:
ratelena [41]2 years ago
8 0

Answer:

I do not know the Answer I'm just trying to get my point

Step-by-step explanation:

Thank you

Thank you

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Someone please help me with this question
mrs_skeptik [129]

Answer:

10x

Step-by-step explanation:

By definition

(f\codt g)(x)=f(x)\cdot g(x)

So we just need to multiply the two functions

(f\cdot g)(x)= f(x)\cdot g(x)\\=\sqrt{2x}\cdot \sqrt{50x}\\=\sqrt{(2x)\cdot (50x)}=\sqrt{100x^2}\\=10\sqrt{x^2}\\=10x \text{ since x is non negative}

8 0
2 years ago
If an object is launched at an angle of 28° with an initial velocity of 133 ft./s from a height of 6 feet how many seconds will
Tema [17]

Answer:

Hence after  3.98 sec  i.e  4 sec Object will hit the ground  .

Step-by-step explanation:

Given:

Height= 6 feet

Angle =28 degrees.

V=133 ft/sec

To Find:

Time in seconds after which it will hit the ground?

Solution:

<em>This problem is related to projectile motion for objec</em>t

First calculate the Range for object  and it is given by ,

R=v^2Sin(2Ф)/g

Here R= range  g= acceleration due to gravity =9.8 m/sec^2

1m =3.2 feet

So 9.8 m, equals to 9.8 *3.2=31.36 ft

So g=31.36 ft/sec^2. and 2Ф=2(28)=56

R=133^2*Sin(56)/31.36

R=14664.84/31.36

R=467.62  fts

Now using Formula for time and range as

R=VxT

Vx is horizontal velocity

Vx=V*cosФ

Vx=133*cos(28)

Vx=117.43  ft/sec

So above equation becomes as ,

467.62=117.43*T

T=467.62/117.43

T=3.98 sec

T is approximately equals to 4 sec.

4 0
3 years ago
Simplify (11+4)x10+5
AURORKA [14]

Answer:

155

Step-by-step explanation:

= (15)x10+5

= 150+5

= 155

4 0
3 years ago
Read 2 more answers
What is this fraction as a decimal?
expeople1 [14]
14.4
hope this helps:)
6 0
3 years ago
Explain how to solve linear equations.
muminat

Answer:

that means you need to find the surface area, but not the part that is touching the ground or the bottom.

3 0
3 years ago
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