Answer:
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Step-by-step explanation:
Calculation for the equation that can be
use to find the maximum and minimum times for the track team
Using this equation to find the maximum times for the track team
T maximum=T average -7.8 seconds
T maximum=64.6 seconds-7.8 seconds
Using this equation to find the minimum times for the the track team
T minimum=T average +7.8 seconds
T minimum=64.6 seconds +7.8 seconds
Therefore the equation for the maximum and minimum times for the track team are :
T maximum=T average -7.8 seconds
T minimum=T average +7.8 seconds
Answer:
x^12
Step-by-step explanation:
multiply 4 and 3
x^4*3 = x^12
The answer is Y equals -7+5x
Answer:
x=11(12y-15)
Step-by-step explanation:
4x(3y-2)=7x+11
12xy-8x=7x+11
12xy-8x-7x=11
12xy-15x=11
x(12y-15)=11
x(12y-15)/(12y-15)=11/(12y-15)
x=11/(12y-15)
