which graph could represent y, the amount owed on a car loan, as regular payments are made each month, x?
2 answers:
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<u>Answer</u>:
Equation of a line perpendicular to and passes through the point ( 2 , − 6 ) is
5x – 7y = 4.
<u>Explanation</u>:
Need to write equation of line perpendicular to y = 7/5x + 6 and passes through the point ( 2 , − 6 )
Generic slope intercept form of a line is given by y = mx + c , where m = slope of the line.
On comparing the given slope intercept form of given equation with generic slope intercept form y = mx + c , we can say that for line , slope m = 7/5
Product of slope of perpendicular line is -1 .
Let say slope of required line perpendicular to y = 7/5x + 6 is represented by m1
And as Product of slope of perpendicular line is -1 .
=>
=>
=>
so now we need to find the equation of a line whose slope is and passing through (2 , -6).
Equation of line passing through (x1 , y1) and having slope of m is given by
(y – y1) = m (x – x1)
In our case x1 = 2 and y1 = -6 and m = -5/7
Substituting the values in equation of line we get
=>
=>
=> 7(y +6) = -5x +10
=> 5x – 7y = 10 – 6
=> 5x – 7y = 4
Hence equation of a line perpendicular to and passes through the point ( 2 , − 6 ) is
5x – 7y = 4.
Step-by-step explanation:
n = 52
x bar = 122.31
standard deviation sd = 38.75
1. the hypothesis:
null hypothesis
h0: μ ≤ 35
alternative hypothesis
h1: μ > 35
2.
we have been given the sd of the sample but not that of the population. so what we are supposed to use here is the t test and not the z test. the following conditions have to be met.
- population has to be normal
- sample size has to be more than 30. we have sample size = 52 in this question.
3.
=
= 87.31/5.37
= 16.26
using the T distribution function in excel, the p value was calculated and found to be approximately equal to 0.
TDIST(16.26, 51, 1)
since p value is very small we reject the null and accept the alternate hypothesis.
4. from the result above the answer to this question is yes
