First, we need to add 2/6 and 2/5.
2/6 can be simplified to 1/3
We need to have 1/3 and 2/5 have the same denominator. 3 and 5's LCM (least common multiply) is 15.
Multiply both the numerator and denominator of 1/3 by 5. This equals 5/15.
Multiply both the numerator and denominator of 2/5 by 3. This equals 6/15.
5/15 plus 6/15 is 11/15. This means that Jack's 6000 dollars is 4/15.
Let's say that x is the total amount invested by all three.
6000/x would equal 4/15.
Solve this by multiply 6000 by 15 and 4 by x and making these two equal each other.
90000 would equal 4x. Divide both sides by 4 to get x.
90000 divided by 4 would be 22500.
4/15 is the fraction by Jack
22500 is the total amount invested by all 3
Answer:
p = -2 ±sqrt( 5)
Step-by-step explanation:
p^2 + 4p = 1
Take the coefficient of p
4
Divide by 2
4/2 =2
Square it
2^2 = 4
Add it to each side
p^2 + 4p+4 = 1+4
(p+2) ^2 = 5
Take the square root of each side
sqrt((p+2) ^2) =±sqrt( 5)
p+2 = ±sqrt( 5)
Subtract 2 from each side
p+2-2 = -2 ±sqrt( 5)
p = -2 ±sqrt( 5)
Answer: a) about 450
Step-by-step explanation:
50 multiplied by 9 is 450 and its asking for an approximate so it would be anything near 450
Hi there!
Many things we do in everyday life have a variety of ways we can go about accomplishing them, but we most often choose the most practical and efficient method.
Efficiency saves time and prevents over-complication, which may lead to errors.
We might need to identify the specifics of the task and its circumstances to be able to determine the most efficient method to do it.
Solving a quadratic equation, we also must think about the most efficient method that can lead us to the correct answer. And doing so, we must identify the circumstances of the equation; Can it be solved by factoring? Is it easy to factor? What form is this quadratic equation in?
For example, let's say we're given the equation (x-1)(x+2)=0. This is an equation in factored form. In these kinds of scenarios, we can <em>easily</em> solve by setting each term equal to 0 (the Zero Product Property). This is the <em>most efficient </em>method:
x-1=0 --> x=1
x+2=0 --> x=-2
I hope this helps!
The answer is in my attachment
