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Serhud [2]
3 years ago
7

the initial velocityof a particle along x axis is u at t=0 x=0 and its acceleration is given by a =2x then whats the correct equ

ation for v^2= u^2 +2as​
Physics
1 answer:
miskamm [114]3 years ago
8 0

Answer:

v² = u² + 2x²

Explanation:

v² = u² + 2as​ is only valid for constant acceleration.  Here, the acceleration is a function of position.  We can find the function of velocity by integrating.  Acceleration is the derivative of velocity with respect to time:

a = 2x

dv/dt = 2x

Apply chain rule:

dv/dt = dx/dt × dv/dx

dv/dt = v × dv/dx

Therefore:

v dv/dx = 2x

Separate the variables and integrate:

v dv = 2x dx

½ v² |ᵤᵛ = x² |₀ˣ

½ (v² − u²) = x²

v² − u² = 2x²

v² = u² + 2x²

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Which of the following compounds does not contain molecules? A. H2 B. NaCl C. CO2 D. H2O
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B. NaCl

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4 years ago
Read 2 more answers
A container with volume 1.83 L is initially evacuated. Then it is filled with 0.246 g of N2. Assume that the pressure of the gas
alisha [4.7K]

Answer:

The  pressure is  P =   1652 \  Pa

Explanation:

From the question we are told that

    The  volume of the container is  V  =  1.83  \ L =  1.83 *10^{-3 } \  m^3

     The mass of  N_2 is  m_n  =  0.246 \ g =  0.246 *10^{-3} \ kg

     The root-mean-square velocity is  v =  192 \ m/s

The  root -mean square velocity is mathematically represented as

      v =  \sqrt{ \frac{3 RT}{M_n  } }

Now the ideal gas law is mathematically represented as

      PV  =  nRT

=>   RT  =  \frac{PV}{n }

Where n is the number of moles which is mathematically represented as

         n =  \frac{ m_n }{M }

Where  M  is the molar mass of  N_2

So  

        RT  =  \frac{PVM_n }{m _n  }

=>    v =  \sqrt{ \frac{3 \frac{P* V  *  M_n }{m_n } }{M_n  } }

=>    v =  \sqrt{  \frac{ 3 *  P* V  }{m_n } } }

=>   P =   \frac{v^2   *  m_n}{3 *    V  }

substituting values

    =>    P =   \frac{( 192)^2   *  0.246 *10^{-3}}{3 *    1.83 *10^{-3} }

=>         P =   1652 \  Pa

       

     

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Answer:

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Explanation:

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Answer:

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