Answer: 800
Explanation:
1/2 x m x v^2 = m x g x h
KE = 10 x 10 x 8
KE= 800
Answer:

Explanation:
The vertical component of the initial velocities are

If we ignore air resistance, and let g = -9.81 m/s2. The the time it takes for the projectiles to travel, vertically speaking, can be calculated in the following motion equation




So the ratio of the times of the flights is

Answer:
No you could not do that because if you tried even if you where to go super fast they would feel a breif second of pain before being completely riped from there body
A scientific law is the simple mathematical expression of the relationship involved. A principle is the same relationship expressed in words. A theory is the explanation of the facts that make up the relationship.