Answer:
Average net force, F = 15157.15 N
Explanation:
It is given that,
The mass of the car and riders is, 
Initial speed of the car, u = 0
Final speed of the car, v = 43.4 m/s
Time, t = 8.59 seconds
We need to find the average net force exerted on the car and riders by the magnets. It can be calculated using second law of motion as :
F = m a


F = 15157.15 N
So, the average net force exerted on the car and riders by the magnets. Hence, this is the required solution.
An object in motion lolllsss
Given that,
Current = 4 A
Sides of triangle = 50.0 cm, 120 cm and 130 cm
Magnetic field = 75.0 mT
Distance = 130 cm
We need to calculate the angle α
Using cosine law




We need to calculate the angle β
Using cosine law




We need to calculate the force on 130 cm side
Using formula of force



We need to calculate the force on 120 cm side
Using formula of force


The direction of force is out of page.
We need to calculate the force on 50 cm side
Using formula of force


The direction of force is into page.
Hence, The magnitude of the magnetic force on each of the three sides of the loop are 0 N, 0.1385 N and 0.1385 N.
Frequency is 1 over the period. Hence, the frequency is 1/18.