All categories

4 years ago

Someone please help me20 POINTS

Physics

1 answer:

Marta_Voda [28]4 years ago

7 0

1: B
2: C Sediments were deposited in continuous sheets that spanned the body of water that they were deposited in
3: A Erosion is the action and movement of a surface process

You might be interested in

What is happening if energy input remains constant and voltage remains the same in a circuit, but the current decreases?

DENIUS [597]

Ohm's law deals with the relation between voltage and current in an ideal conductor. It states that: Potential difference across a conductor is proportional to the current that pass through it. It is expressed as V=IR. The correct answer from the choices listed above is option A. The resistance has increased.

8 0

3 years ago

Read 2 more answers

The index of refraction for red light in water is 1.331 and that for blue light is 1.340. A ray of white light enters the water

Alex Ar [27]

Answer:

(a) 47.08°

(b) 47.50°

Explanation:

Angle of incidence = 78.9°

For blue light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for blue light which is 1.340

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.340}$

${sin\theta_2}=0.7323$

Angle of refraction for blue light = sin⁻¹ 0.7323 = 47.08°.

For red light :

Using Snell's law as:

$\frac {sin\theta_2}{sin\theta_1}=\frac {n_1}{n_2}$

Where,

Θ₁ is the angle of incidence

Θ₂ is the angle of refraction

n₂ is the refractive index for red light which is 1.331

n₁ is the refractive index of air which is 1

So,

$\frac {sin\theta_2}{sin{78.9}^0}=\frac {1}{1.331}$

${sin\theta_2}=0.7373$

Angle of refraction for red light = sin⁻¹ 0.7373 = 47.50°.

5 0

3 years ago

(V) What are the objectives of the space mission?

Svetach [21]

Explanation:

I hope this helps, I got this from another person

3 0

3 years ago

An automobile with a mass of 1240.00 kg has 3.99 m between

Vitek1552 [10]

Answer:

$948.15248\ N$

$5134.04751\ N$

Explanation:

$F_f$ = Force on front wheels

$F_r$ = Force on rear wheels

Distance between CG and rear wheel = 3.99-0.622 = 3.368 m

$F_r=1240\times 9.81-F_f$

As the forces are conserved we have

$(1240\times 9.81-F_f)3.368=F_f\times 0.622\\\Rightarrow 12164.4-F_f=\dfrac{0.622F_f}{3.368}\\\Rightarrow 12164.4-F_f=0.18467F_f\\\Rightarrow F_f=\dfrac{12164.4}{1.18467}\\\Rightarrow F_f=10268.09503\ N$