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sleet_krkn [62]

4 years ago

10

Someone please help me20 POINTS

1 answer:

Marta_Voda [28]4 years ago

7 0

1: B
2: C <span>Sediments were deposited in continuous sheets that spanned the body of water that they were deposited in</span>
3: A Erosion is the action and movement of a surface process

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djverab [1.8K]

<span>In this example, what is the independent variable?

a) The time of day assigned to exercise
<u>b) How long someone spent exercising </u>
c) Type of exercise
d) How many students are in the class

</span><span>What is the only form of psychological research that can determine cause and effect?

<u>a) Comparative Study </u>
b) Correlational Study
c) Survey
d) Experiment</span>

4 0

3 years ago

Read 2 more answers

A particle with charge Q is on the y axis a distance a from the origin and a particle with charge q is on the x axis a distance

Natalka [10]

Answer:

Explanation:

Force on q due to Q

= k Qq / ( a² + d²)

x component

= k Qq / ( a² + d²) x d /√ ( a² + d²)

F = kQq d/ ( a² + d²)³/²

differentiating F with respect to d

dF / Dd = kQq [ d. -3/2 ( a² + d²)⁻⁵/² 2d + ( a² + d²)⁻³/²]=0 for maximum F

- 3d² / ( a² + d²) + 1 = 0

a² + d² = 3 d²

a² = 2d²

d = a / √2

8 0

4 years ago

The ______________________ of ______________________ in the cores of terrestrial worlds are responsible for ____________________

Sedaia [141]

Hi there! I’m bored and waiting for someone to respond to my question so I’m scrolling

5 0

2 years ago

A beam of light traveling in air is incident on a slab of transparent material. The incident beam makes an angle of 40.0°with th

Oksanka [162]

Answer:

Answer is in the attachment.

8 0

3 years ago

A 57.0 kg person in a

kakasveta [241]

Answer:

The linear speed of the car is approximately 27.30 m/s

Explanation:

The question parameters are;

The mass of the person on the rollercoaster, m = 57.0 kg

The radius of the rollercoaster track, r = 42.7 m

The normal force felt by the person, F = 995 N

The centripetal force acting on the person keep the circular motion is given by the following equation;

$Centripetal \, force \ F_c = \dfrac{m \times v^2}{r}$

Where;

v = The linear velocity of motion = The linear speed of the car

The centrifugal force, F, is the force normal force felt by the person and is equal to the centripetal force, therefore, we have;

$Centripetal \, force \ F_c = Centrifugal \, force \ F = \dfrac{m \times v^2}{r}$

From which we have;

$F = 995 = \dfrac{57 \times v^2}{42.7}$

$\therefore v = \sqrt{\dfrac{995 \times 42.7}{57} } \approx 745.38$

The linear speed of the car = v ≈ 27.30 m/s

The angular speed of the car, ω = v/r ≈ 27.30/42.7 ≈ 0.639 rad/s

8 0

3 years ago