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Leno4ka [110]
2 years ago
12

Is 5 celsius cold or hot

Mathematics
1 answer:
tatyana61 [14]2 years ago
7 0
5 celsius is cold, I believe.
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Please help me with this question​
netineya [11]

Answer

777

Step-by-step explanation:

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3 0
3 years ago
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Charlie ran 5 miles in 51.5 minutes. Use the equation 5r=51.5 to find r, the average rate he ran.
jenyasd209 [6]
5r = 51.5
r = 51.5 / 5
r = 10.3
6 0
3 years ago
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Simplify:<br> {[(16 ÷ 4) × (2 × 6)] ÷ 6} + 4 =
borishaifa [10]

Answer:

12

Step-by-step explanation:

divided 16 by 4 which is 4. then multiply 2 by 6, which is 12. then multiply 4 by 12. Remember to always do ( ) first. 4 by 12 is 48. Then do 48 divided by 6 which is 8. then add 8+4 which is 12.

4 0
3 years ago
Multiply. Check picture.
VashaNatasha [74]

The answer is 3x^4-13x^3-x^2-11x+6.

Solution:

Use algebraic identity: a^m\times a^n=a^{m+n}

For example: x^2\times x=x^{2+1}=x^3

Given expression (x^2-5x+2) and (3x^2+2x+3).

To multiply these equations.

(x^2-5x+2)\times(3x^2+2x+3)

             =x^2(3x^2+2x+3)-5x(3x^2+2x+3)+2(3x^2+2x+3)

             =(3x^4+2x^3+3x^2)+(-15x^3-10x^2-15x)+(6x^2+4x+6)

             =3x^4+2x^3+3x^2-15x^3-10x^2-15x+6x^2+4x+6

Combine like terms together.

             =3x^4+(2x^3-15x^3)+(3x^2-10x^2+6x^2)-15x+4x+6

             =3x^4-13x^3-x^2-11x+6

(x^2-5x+2)\times(3x^2+2x+3)=3x^4-13x^3-x^2-11x+6

Hence the answer is 3x^4-13x^3-x^2-11x+6.

3 0
3 years ago
EasyElectrics supermarket orders light bulbs from suppliers, AA Electronics and AAA Electronics. EasyElectrics purchases 30% of
saw5 [17]

Answer: (a) 0.006

               (b) 0.027

Step-by-step explanation:

Given : P(AA) = 0.3 and P(AAA) = 0.70

Let event that a bulb is defective be denoted by D and not defective be D';

Conditional probabilities given are :

P(D/AA) = 0.02 and P(D/AAA) = 0.03

Thus P(D'/AA) = 1 - 0.02 = 0.98

and P(D'/AAA) = 1 - 0.03 = 0.97

(a) P(bulb from AA and defective) = P ( AA and D)

                                                       = P(AA) x P(D/AA)

                                                       = 0.3 x 0.02 = 0.006

(b) P(Defective) = P(from AA and defective) + P( from AAA and defective)

                         = P(AA) x P(D/AA) + P(AAA) x P(D/AAA)

                         = 0.3(0.02) + 0.70(0.03)

                         = 0.027

3 0
3 years ago
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