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3 years ago

15

Louise walked past Thurman at a speed of 2 feet per second. After 5 seconds, Thurman started after her at a speed of 4 feet per

second. How many seconds did it take Thurman to catch Louise?

1 answer:

mylen [45]3 years ago

3 0

Answer:

at 20 seconds

Step-by-step explanation:

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NEED HELP ASAP!!!!!!!!!!!<br><br> 2. Solve for x<br> 3. Solve for x

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Answer:

2. x = 47

3. x = 2

Step-by-step explanation:

These problems involve proportions, or equivalent ratios. You can solve for 'x' in each by using cross-multiplication and division.

2. 28(7) = 4(x + 2)

Distribute = 196 = 4x + 8

Subtract 8 from both sides: 196 - 8 = 4x + 8 - 8 or 188 = 4x

Solve for x: x = 47

3. 2(2x + 7) = 11(3x - 4)

Distribute: 4x + 14 = 33x - 44

Add 44 to both sides: 4x + 14 + 44 = 33x - 44 + 44 or 4x + 58 = 33x

Subtract 4x from both sides: 4x + 58 - 4x = 33x - 4x or 58 = 29x

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4 years ago

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Answer:

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Step-by-step explanation:

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3 years ago

cylinder shaped can needs to be constructed to hold 200 cubic centimeters of soup. The material for the sides of the can costs 0

Dafna11 [192]

Answer:

Radius=2.09 cm

Height,h=14.57 cm

Step-by-step explanation:

We are given that

Volume of cylinderical shaped can=200 cubic cm.

Cost of sides of can=0.02 cents per square cm

Cost of top and bottom of the can =0.07 cents per square cm

Curved surface area of cylinder= $2\pi rh$

Area of circular base=Area of circular top= $\pi r^2$

Total cost,C(r)= $0.02\times 2\pi rh+2\pi r^2\times 0.07$

Volume of cylinder, $V=\pi r^2 h$

$200=\pi r^2 h$

$h=\frac{200}{\pi r^2}$

Substitute the value of h

$C(r)=0.02\times 2\pi r\times \frac{200}{\pi r^2}+2\pi r^2\times 0.07$

$C(r)=\frac{8}{r}+0.14\pi r^2$

Differentiate w.r.t r

$C'(r)=-\frac{8}{r^2}+0.28\pi r$

$C'(r)=0$

$-\frac{8}{r^2}+0.28\pi r=0$

$0.28\pi r=\frac{8}{r^2}$

$r^3=\frac{8}{0.28\pi}=9.095$

$r=(9.095)^{\frac{1}{3}}=2.09$

Again, differentiate w.r.t r

$C''(r)=\frac{16}{r^3}+0.28\pi$

Substitute the value of r

$C''(2.09)=\frac{16}{(2.09)^3}+0.28\pi=2.63>0$

Therefore,the product cost is minimum at r=2.09

h= $\frac{200}{\pi (2.09)^2}=14.57$

Radius of can,r=2.09 cm

Height of cone,h=14.57 cm

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Find the image of A(-2,4) under a translation (x,y)->(x-2,y-3)

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Answer:

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2 years ago