Answer: (a) e ^ -3x (b)e^-3x
Step-by-step explanation:
I suggest the equation is:
d/dx[integral (e^-3t) dt
First we integrate e^-3tdt
Integral(e ^ -3t dt) as shown in attachment and then we differentiate the result as shown in the attachment.
(b) to differentiate the integral let x = t, and substitute into the expression.
Therefore dx = dt
Hence, d/dx[integral (e ^-3x dx)] = e^-3x
Answer:
y=sqrt((x+a)/-2b))
F=(5/9)C+32
Can't read the rest
Step-by-step explanation:
-2by^2=x+a
y^2=(x+a)/-2b
y=sqrt((x+a)/-2b))
F-32=(5/9)C
F=(5/9)C+32 (The actual Fahrenheit-Celcius formula)
NOTE: The other pictures cannot be opened.
Given that ΔBDA is similar to ΔBDC and:
AD≡DC
AB≡BC
BD≡BD (shared side)
then the best postulate to use is the side-side-side (SSS) postulate.
Answer: SSS
Answer:
Factored form: -2(x + 7) = 8, x = -11 (brainliest)?
Step-by-step explanation:
-2(x + 7) = 8
x + 7 = 8 / -2
x + 7 = -4
x = -4 - 7
= -11
Answer:
glucose that is what i think but it looks not right for your letter.
Step-by-step explanation:
