2 years ago

According to an almanac, 60% of adult smokers started smoking before turning 18 years old.

1 answer:

4 0

A) mean = np
0.6(200) = 120
SD^2= np(1-p)
SD = sqrt(200(0.6)(1-0.6))
SD = 6.928
B) the mean of binomial distribution in this case is the average number of samples you’ll have to take before you achieve a sample of 200 where 60% of smokers who started smoking before 18.

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According to an​ almanac, 60% of adult smokers started smoking before turning 18 years old.

According to an almanac, 60% of adult smokers started smoking before turning 18 years old.