Circumference of a circle = 2πr
Circumference of the whole circle= 2π(30) = 60π
360 - 90 = 270
Length XPY = 270/360 x 60π = 45π
Answer: 45π m
Answer:
20 inches
Step-by-step explanation:
Since the cape is trapezoid shaped and has an area of 600 in², the area of a trapezoid is given by
A =1/2(a + b)h where a = length along the top of the cape = 24 in, b = length along the bottom of the cape = 36 in and h = height of the cape
So, h = 2A/(a + b)
= 2 × 600 in²/(24 in + 36 in)
= 1200 in²/60 in
= 20 in
So, the height of the cape is 20 inches
Answer:
- sin(x) = 1
- cos(x) = 0
- cot(x) = 0
- csc(x) = 1
- sec(x) = undefined
Step-by-step explanation:
The tangent function can be considered to be the ratio of the sine and cosine functions:
tan(x) = sin(x)/cos(x)
It will be undefined where cos(x) = 0. The values of x where that occurs are odd multiples of π. The smallest such multiple is x=π/2. The value of the sine function there is positive: sin(π/2) = 1.
The corresponding trig function values are ...
tan(x) = undefined (where sin(x) >0)
sin(x) = 1
cos(x) = 0
__
And the reciprocal function values at x=π/2 are ...
cot(x) = 0 . . . . . . 1/tan(x)
csc(x) = 1 . . . . . . .1/sin(x)
sec(x) = undefined . . . . . 1/cos(x)
80 square units
Divide the figure into 4 small triangles, 2 rectangles, and one big rectangle on the center.
Area of ONE small triangle:
1/2 • 2 • 2 = 2 square units
Multiply that by 4 because we have 4 small triangles: 2 • 4 = 8 square units
Area of ONE small rectangle:
2 • 6 = 12 square units
Multiply that by 2 bcos we have 2 of those rectangles: 12 • 2 = 24 square units
Area of the big rectangle on the center:
6 • 8 = 48 square units
ADD the area of the big rectangle, 4 small triangles, and 2 small rectangles:
48 + 24 + 8 = 80
FINAL ANSWER: 80 square units
BRAINLIEST WILL BE APPRECIATED IF I GOT THIS RIGHT (pls comment me back if my answer was correct)
Have a nice day -SpaceMarsh
Answer:
111011
Step-by-step explanation:
Following the binary rule we can find the base 2 presentation of the decimal number 59.
To find the binary equivalence of 59 we use the sum of powers of 2.







Now we take our number and find out what the binary number will by taking our largest number closest to the number first.
59 = 32
We chose the number 32 since 64 will be a larger value than 59.
We then check how much we have to add to 32 to get 59.
59 = 32 + 27
We then look for the closest number to 27 in our powers of 2.
59 = 32 + 16
Now we check again for how much we need left to get a total of 59.
59 = 32 + 16 + 11
Now we repeat the same process of finding which value in the powers of 2 are closest to the number.
59 = 32 + 16 + 8 + 3
59 = 32 + 16 + 8 + 2 + 1
Now since we already have a total of 59, our binary number will be all the numbers present will have a value of 1 and the numbers now used will have a number of 0.
32 16 8 4 2 1
This can also be represented as:
2^5 2^4 2^3 2^1 2^0
Now we have to include the numbers that we skipped to get the total binary number.
32 16 8 4 2 1
1 1 1 0 1 1
This can be represented as:
59 = 32 16 + 8 + 0 + 2 + 1
1 1 1 0 1 1