Answer:
An equilateral triangle has all three sides equal, and all three interior angles equal, too. In this case, each interior angle of an equilateral triangle is 60 degrees.
Step-by-step explanation:
Answer:
500
Step-by-step explanation:
hope it helps you
tic tac toe
Answer:
It's true, if that's what your asking.
Step-by-step explanation:
5/6 = 0.833 to 3 sig.fig.
4/5 = 0.800 to 3 sig.fig.
6/7 = 0.857 to 3 sig.fig.
0.833 is more than 0.800 and less than 0.857.
Currently, you would ask "How long does it take to get from Rotherham to London?" You would do 156/60, which would be 2.6 hours. 2.6 hours is 156 minutes (2 hours, 36 minutes).
9:36 is when Kim would reach London, so yes.
60 = a * (-30)^2
a = 1/15
So y = (1/15)x^2
abc)
The derivative of this function is 2x/15. This is the slope of a tangent at that point.
If Linda lets go at some point along the parabola with coordinates (t, t^2 / 15), then she will travel along a line that was TANGENT to the parabola at that point.
Since that line has slope 2t/15, we can determine equation of line using point-slope formula:
y = m(x-x0) + y0
y = 2t/15 * (x - t) + (1/15)t^2
Plug in the x-coordinate "t" that was given for any point.
d)
We are looking for some x-coordinate "t" of a point on the parabola that holds the tangent line that passes through the dock at point (30, 30).
So, use our equation for a general tangent picked at point (t, t^2 / 15):
y = 2t/15 * (x - t) + (1/15)t^2
And plug in the condition that it must satisfy x=30, y=30.
30 = 2t/15 * (30 - t) + (1/15)t^2
t = 30 ± 2√15 = 8.79 or 51.21
The larger solution does in fact work for a tangent that passes through the dock, but it's not important for us because she would have to travel in reverse to get to the dock from that point.
So the only solution is she needs to let go x = 8.79 m east and y = 5.15 m north of the vertex.
