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butalik [34]
3 years ago
9

Solve the equation and explain​

Mathematics
1 answer:
miss Akunina [59]3 years ago
8 0
Start by simplifying the equation by cross multiplying

9(z+1) = 3z

then distribute 9 into the brackets

9z + 9= 3z

then move the constant to the right hand side and change its sign

9z = 3z -9

then move the variable to the left hand side and change its sign

9z - 3z = -9

collect like terms

6z = - 9

then divide both equations by 6 to get z by itself

z = -9/6

simplify the fraction

z = -3/2
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Please help me i'll mark brainliest.
Artyom0805 [142]

Answer:

it should be 8 and 5, the first one

8 0
3 years ago
Read 2 more answers
Find the least common multiple of these two expressions. 15x^7y^3u^8 and 6y^4u^5
snow_tiger [21]

Answer:

30x^7y^4u^8

Step-by-step explanation:

We have been given two expressions 15x^7y^3u^8 and

6y^4u^5

Now we need to find out least common multiple of these two expressions.

First we need to find out what is common factor of both expressions. 15x^7y^3u^8 and

6y^4u^5

Least common multiple means find the expression which can be divided by both expressions.

15 and 6 both goes into 30

so 30 is part of LCM (least common multiple )

Now pickup the highest exponent of each variable.

So we get x^7y^4u^8

Hence required least common multiple is 30x^7y^4u^8

8 0
3 years ago
Can someone please help me find the measure of angle ABO?
lara [203]

Answer:

m<ABO = 22 deg

Step-by-step explanation:

A tangent intersects a circle at the point of tangency making a right angle with the radius drawn to that point. That means that <BAO is a right angle and measures 90 deg. That makes the other two angles of the triangle complementary with a sum of 90 deg.

m<O + m<B = 90

68 + m<B = 90

m<B = 22

Answer: m<ABO = 22 deg

3 0
3 years ago
Solving a trigonometric equation involving an angle multiplied by a constant
PIT_PIT [208]

In these questions, we need to follow the steps:

1 - solve for the trigonometric function

2 - Use the unit circle or a calculator to find which angles between 0 and 2π gives that results.

3 - Complete these angles with the complete round repetition, by adding

2k\pi,k\in\Z

4 - these solutions are equal to the part inside the trigonometric function, so equalize the part inside with the expression and solve for <em>x</em> to get the solutions.

1 - To solve, we just use algebraic operations:

\begin{gathered} \sqrt[]{3}\tan (3x)+1=0 \\ \sqrt[]{3}\tan (3x)=-1 \\ \tan (3x)=-\frac{1}{\sqrt[]{3}} \\ \tan (3x)=-\frac{\sqrt[]{3}}{3} \end{gathered}

2 - From the unit circle, we can see that we will have one solution from the 2nd quadrant and one from the 4th quadrant:

The value for the angle that give positive

+\frac{\sqrt[]{3}}{3}

is known to be 30°, which is the same as π/6, so by symmetry, we can see that the angles that have a tangent of

-\frac{\sqrt[]{3}}{3}

Are:

\begin{gathered} \theta_1=\pi-\frac{\pi}{6}=\frac{5\pi}{6} \\ \theta_2=2\pi-\frac{\pi}{6}=\frac{11\pi}{6} \end{gathered}

3 - to consider all the solutions, we need to consider the possibility of more turn around the unit circle, so:

\begin{gathered} \theta=\frac{5\pi}{6}+2k\pi,k\in\Z \\ or \\ \theta=\frac{11\pi}{6}+2k\pi,k\in\Z \end{gathered}

Since 5π/6 and 11π/6 are π radians apart, we can put them together into one expression:

\theta=\frac{5\pi}{6}+k\pi,k\in\Z

4 - Now, we need to solve for <em>x</em>, because these solutions are for all the interior of the tangent function, so:

\begin{gathered} 3x=\theta \\ 3x=\frac{5\pi}{6}+k\pi,k\in\Z \\ x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z \end{gathered}

So, the solutions are:

x=\frac{5\pi}{18}+\frac{k\pi}{3},k\in\Z

4 0
1 year ago
Assignment Active Identifying the Rules of Exponents to Evaluate Which rules of exponents will be used to evaluate the expressio
Natali [406]

Answer:

its 44

Step-by-step explanation:

because IRS 444 j utf d funk nhc ddh

3 0
2 years ago
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