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Andre45 [30]
3 years ago
10

What is the equation of the axis of symmetry of the graph of y-ax? +bx+c?

Mathematics
1 answer:
Svetllana [295]3 years ago
6 0

Answer:

x= -b/2a

Step-by-step explanation:

hello :

 y = ax²+bx+c .... (a≠0)

the equation of the axis of symmetry of this graph is : x= -b/2a

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<u>Given</u>:

Given that we need to prove the identity \sin x+\sin x \tan ^{2} x=\tan x \sec x

<u>Proof</u>:

Step 1: Factor out the common term sin x, we get;

\sin x\left(1+\tan ^{2} x\right)=tan \ x \ sec \ x

Step 2: Using the identity 1+tan^2 x=sec^2x

\sin x \sec ^{2} x=tan \ x \ sec \ x

Step 3: Reciprocating sec x, we get;

\sin x \cdot \frac{1}{\cos ^{2} x}=tan \ x \ sec \ x

Step 4: Splitting the denominator, we have;

\frac{\sin x}{\cos x} \cdot \frac{1}{\cos x}=tan \ x \ sec \ x

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Answer:

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Step-by-step explanation:

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