Stephen's lunch was $8.33 and Jahmya's lunch was $7.48. Stephen's lunch cost more, by 85¢. If Jahmya leaves a tip, she receives $18.25 back. Hope this helps God Bless!
Answer:
SHe put the decimal point in the wrong spot, it's suppose to be 43.89
Step-by-step explanation:
Answer:
Check attachment for the diagram
Step-by-step explanation:
Given two points A and B in the diagram attached, we see that exactly one line exists between these points.



p, li { white-space: pre-wrap; }
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now on 2)
if the denominator has a higher degree than the numerator, the horizontal asymptote is y = 0, or the x-axis,
in this case, the numerator has a degree of 0, the denominator has 4, thus y = 0
vertical asymptotes occur when the denominator is 0, that is, when the fraction becomes undefined, and for this one, that occurs at
or the y-axis
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now on 3)

now, let's see some transformations templates


now, let's take a peek at g(x)
