Answer:
0.2
Step-by-step explanation:
3
10
÷
1 1
2
=
3
10
÷
3
2
=
3
10
×
2
3
=
3 × 2
10 × 3
=
6
30
=
6 ÷ 6
30 ÷ 6
=
1
5
Answer:
Any [a,b] that does NOT include the x-value 3 in it.
Either an [a,b] entirely to the left of 3, or
an [a,b] entirely to the right of 3
Step-by-step explanation:
The intermediate value theorem requires for the function for which the intermediate value is calculated, to be continuous in a closed interval [a,b]. Therefore, for the graph of the function shown in your problem, the intermediate value theorem will apply as long as the interval [a,b] does NOT contain "3", which is the x-value where the function shows a discontinuity.
Then any [a,b] entirely to the left of 3 (that is any [a,b] where b < 3; or on the other hand any [a,b] completely to the right of 3 (that is any [a,b} where a > 3, will be fine for the intermediate value theorem to apply.
Answer:
I dont know
Step-by-step explanation:
I
Dont
Know
Goodluck
Answering it tho
The function is decreasing on the interval (-∞,∞)
This means that, throughout the whole graph, the slope is negative.
-0.9 -0.4. Make sense at all???