All categories

2 years ago

Help me pleaseee !!!!!!

Mathematics

1 answer:

exis [7]2 years ago

7 0

17) y= 2(x+2) 18) y= 1.8(x-5) 19) x= 4 20) y= 2.5(x+4) 21) y= 4.3(x+3) 22) y= -2(x+3) 23) y= x+2 24) y= 2.6(x-3)

You might be interested in

A solid oblique pyramid has a square base with edges measuring x cm. The height of the pyramid is (x + 2) cm. Which expression r

zavuch27 [327]

we know that

the volume of a solid oblique pyramid is equal to

$V=\frac{1}{3}*B*h$

where

B is the area of the base

h is the height of the pyramid

in this problem we have that

B is a square

$B=b^{2}$

where

$B=x^{2}\ cm^{2}$

$h=(x+2)\ cm$

substitute in the formula of volume

$V=\frac{1}{3}*x^{2}*(x+2)\\ \\V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}$

therefore

<u>the answer is</u>

$V=\frac{1}{3}*[x^{3} +2x^{2}]\ cm^{3}$

4 0

3 years ago

Read 2 more answers

PLZZZZZZZZZZZ HELP MEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEEE!!!!

Digiron [165]

The answer is 51 liters.

Since they have a direct relationship, set up a direct proportion.
17/476=x/1428
476x3 is 1428 so
17x3=51

3 0

3 years ago

If a and b are rational numbers and 6/(3√2-2√3 ) = a √2-b √3 , then find the values of a and b.

eduard

Answer:

=3–√−13–√+1⋅3–√−13–√−1

=(3–√−1)23–√2−12

=3–√2+12−23–√3−1

=4−23–√2

2−13–√

a=2,b=−1.

Step-by-step explanation:

6 0

3 years ago

Suppose we roll a fair die and let X represent the number on the die. (a) Find the moment generating function of X. (b) Use the

Likurg_2 [28]

Answer:

(a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{2 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

Step-by step explanation:

Given X represents the number on die.

The possible outcomes of X are 1, 2, 3, 4, 5, 6.

For a fair die, $P(X)=\frac{1}{6}$

(a) Moment generating function can be written as $M_{x}(t)$ .

$M_x(t)=\sum_{x=1}^{6} P(X=x)$

$M_{x}(t)=\frac{1}{6} e^{t}+\frac{1}{6} e^{2 t}+\frac{1}{6} e^{3 t}+\frac{1}{6} e^{4 t}+\frac{1}{6} e^{5 t}+\frac{1}{6} e^{6 t}$

$M_x(t)=\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$

(b) Now, find $E(X) \text { and } E\((X^{2})$ using moment generating function

$M^{\prime}(t)=\frac{1}{6}\left(e^{t}+2 e^{2 t}+3 e^{3 t}+4 e^{4 t}+5 e^{5 t}+6 e^{6 t}\right)$

$M^{\prime}(0)=E(X)=\frac{1}{6}(1+2+3+4+5+6)$

$\Rightarrow E(X)=\frac{21}{6}$

$M^{\prime \prime}(t)=\frac{1}{6}\left(e^{t}+4 e^{2 t}+9 e^{3 t}+16 e^{4 t}+25 e^{5 t}+36 e^{6 t}\right)$

$M^{\prime \prime}(0)=E(X)=\frac{1}{6}(1+4+9+16+25+36)$

$\Rightarrow E\left(X^{2}\right)=\frac{91}{6}$

Hence, (a) moment generating function for X is $\frac{1}{6}\left(e^{t}+e^{2 t}+e^{3 t}+e^{4 t}+e^{5 t}+e^{6 t}\right)$ .

(b) $\mathrm{E}(\mathrm{X})=\frac{21}{6} \text { and } E\left(X^{2}\right)=\frac{91}{6}$

6 0

3 years ago

Find the solution of y = 6x + 1 for x = 5.

Fudgin [204]

The solution is D.
By plugging the x value, 5, into the equation:
6*5=30
30+1=31
y=31
the x value is 5 and the y value is 31
(5, 31)
hope that helps!

7 0

3 years ago

Read 2 more answers