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Ad libitum [116K]
2 years ago
13

Rewrite the equation by completing the square 4x^2-4x+1=0

Mathematics
2 answers:
oee [108]2 years ago
8 0

Answer:

4(x - \frac{1}{2} )² = 0

Step-by-step explanation:

Given

4x² - 4x + 1 = 0

To complete the square the coefficient of the x² term must be 1

Factor out 4 from 4x² - 4x

= 4(x² - x) + 1 = 0

add/subtract ( half the coefficient of the x- term )² to x² - x

4(x² + 2(- \frac{1}{2} )x + \frac{1}{4} - \frac{1}{4} ) + 1 = 0

4(x - \frac{1}{2} )² - 1 + 1 = 0

4(x - \frac{1}{2} )² = 0

rewona [7]2 years ago
3 0

Answer:

\huge\boxed{(2x-1)^2=0}

Step-by-step explanation:

(a-b)^2=a^2-2ab+b^2\\\\\text{We have:}\\\\4x^2-4x+1=0\\\\(2x)^2-2(2x)(1)+1^2=0\\\\\bold{a=2x,\ b=1}\\\\\text{Therefore we have:}\\\\(2x-1)^2=0

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Answer:

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7 0
3 years ago
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Mike is working on solving the exponential equation 37^x = 12; however, he is not quite sure where to start.
Rainbow [258]

The solution of the given exponential equation is 0.688.

Given that Mike is working on solving the exponential equation 37ˣ = 12.

An exponential equation is an exponential equation where the power (or)  part of the exponent is a variable.

firstly, we have to slve this equation is by converting it to logarithmic form. Any exponential equation can be transformed into an equivalent logarithmic equation as follows:

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logₐy = x

Now, we will apply this transformation to our equation and we get

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Further, we will apply the change of base formula so that solution is written in terms of base 10 logs:

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Hence, the solution of the given exponential equation 37ˣ=12 is 0.688.

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4 0
1 year ago
What is the range of data in this box plot? what is the median?
jeka57 [31]
Hello!

The range is the lowest number subtracted from the highest number

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The range is 8
------------------------------------------------------------------------------------------------------
To find the median you look at the line that separates the box plot into two sections

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Hope this helps!
8 0
3 years ago
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tankabanditka [31]

Answer:

200

Step-by-step explanation:

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To check we can substitute this value into the question :

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1 year ago
With the information given, can you prove this quadrilateral is a parallelogram?
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Opposite sides are congruent and have the same slope.
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2 years ago
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