Answer: One solution
Step-by-step explanation:
V=7/9
Answer:
its 0=0 1=3 and 2=3
Step-by-step explanation: count how many of the injuries there are for 0. In this case there is none. so how many 1's are there, 3. so put 3 in 1. Now two there is 3 for 2 so put 3 in the 2.
The required probability is 
<u>Solution:</u>
Given, a shipment of 11 printers contains 2 that are defective.
We have to find the probability that a sample of size 2, drawn from the 11, will not contain a defective printer.
Now, we know that, 
Probability for first draw to be non-defective 
(total printers = 11; total defective printers = 2)
Probability for second draw to be non defective 
(printers after first slot = 10; total defective printers = 2)
Then, total probability 
I think it would be (x+7)/7
Even tho you did me dirty i will answer you.
You can subtract the whole number