Answer:
Step-by-step explanation:
cute it into separate parts then add the areas together
Answer:
2/7
Step-by-step explanation:
32 is the correct answer I believe if using PEMDAS method
<u>Part 1) </u>To find the measure of ∠A in ∆ABC, use
we know that
In the triangle ABC
Applying the law of sines

in this problem we have

therefore
<u>the answer Part 1) is</u>
Law of Sines
<u>Part 2) </u>To find the length of side HI in ∆HIG, use
we know that
In the triangle HIG
Applying the law of cosines

In this problem we have
g=HI
G=angle Beta
substitute


therefore
<u>the answer Part 2) is</u>
Law of Cosines
None of these are correct my calculations are 11 tons 2138 Ibs 28 oz