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NISA [10]
3 years ago
15

Please help me out.............

Mathematics
1 answer:
qaws [65]3 years ago
3 0

Since the sides are equal the angels have to be equal too

5x-20=2x+37

3x=57

X=19

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If it is \frac{3}{3(4c+16)}=2c+9, go to AAAAAA
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\frac{3}{3(4c+16)}=2c+9
\frac{1}{4c+16}=2c+9
times 4c+16 to both sides
1=(2c+9)(4c+16)
distribute
1=8c^2+68c+144
minus 1 both sides
0=8c^2+68c+143
use quadratic formula
c=\frac{-17- \sqrt{3} }{4} or \frac{-17+ \sqrt{3} }{4}




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(3/3)(4c+16)=2c+9
1(4c+16)=2c+9
4c+16=2c+9
minus 2c both sides
2c+16=9
minus 16 both sides
2c=-7
divide both sides by 2
c=-7/2
c=-3.5





if it is \frac{3}{3(4c+16)}=2c+9,
c=\frac{-17- \sqrt{3} }{4} or \frac{-17+ \sqrt{3} }{4}


if it is (\frac{3}{3})(4c+16)=2c+9, c=-3.5



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