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3 years ago

4. The mean of 12 numbers is 5.5. Eleven

Mathematics

2 answers:

Mashutka [201]3 years ago

7 0

Answer:

A) 4

B) Mode is 5

C) 10.5

Step-by-step explanation:

A) 62+x/12

(62 + x) ÷ 12 = 5.5 ×12

62 + x = 66

×= 66-62

×=4

B) mode is the highest occuring no which is 5

C) mean has been given as 5.5; mean plus mode= 10.5

ozzi3 years ago

6 0

Answer:

a) 4

b) 5

c) 9

Step-by-step explanation:

a) let the 12th number b x

Mean = sum/n

5.5 = (5+6+5+3+4+5+7+6+9+7+5+x)/12

5.5×12 = 62+x

66 = 62+x

x = 4

b) set is: 3,4,4,5,5,5,5,6,6,7,7,9

Mode is 5 (most frequent)

c) mode+mean = 5+4 = 9

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3 years ago

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Answer:

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We are given with the coordinates $(0,0) , (1,12) \ and \ (2,24)$

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3 years ago

Help me guys thx so much

navik [9.2K]

Answer:

Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

Step-by-step explanation:

Step 1: Multiply

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$(x^2\sqrt{10}*2x^2\sqrt{15} )+(x^2\sqrt{10}*x\sqrt{3x} ) + (-x^2\sqrt{5} *2x^2\sqrt{15}) + (-x^2\sqrt{5} *x\sqrt{3x}$

$(2x^4\sqrt{150} ) + (x^3\sqrt{30x}) + (-2x^4\sqrt{75}) + (-x^3\sqrt{15x} )$

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Answer: Option D, $10x^4\sqrt{6} +x^3\sqrt{30x} -10x^4\sqrt{3} -x^3\sqrt{15x}$

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3 years ago

Read 2 more answers

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Answer:

see explanation!

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2 years ago

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shepuryov [24]

Answer:

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