An elliptical equation is in the form
Ax^2+Bx+Cy^2+Dy+E=0
the equation is a Hyperbola. When x and y are both squared, and exactly one of the coefficients is negative and exactly one of the coefficients is positive.
1-49x^2-98x-64y^2+256y-2831=0
2-4x^2+32x-25y^2-250y+589=0
3-81x^2+512x-64y^2-324y-3836=0
Answer:
Length: 5 ft; width: 4 ft.
Step-by-step explanation:
A = LW formula for area of rectangle
(2x + 1)(2x) = 20 substitute length, width, and area into formula
4x² + 2x - 20 = 0 use the distributive property to multiply out left side
2x² + x - 10 = 0 divide both sides of equation by 2
(2x + 5)(x - 2) = 0 factor out trinomial
2x + 5 = 0 or x - 2 = 0 use zero product rule to solve for x
2x = -5 or x = 2 subtract 5 from both sides; add 2 to both sides
x = -5/2 or x = 2
We discard x = -5/2 since it would give negative length and width, and the length and width cannot be negative.
Length: 2x + 1 = 2(2) + 1 = 5
Width: 2x = 2(2) = 4
Length: 5 ft; width: 4 ft.
A suitable calculator can row-reduce the augmented matrix.
first number: 3
second number: 1
third number: 8
Answer:
Step-by-step explanation:
f(x)= (x - 3)(x - 5)
f(x) = x^2 - 5x - 3x + 15
f(x) = x^2 - 8x + 15
Answer is A
Answer:
It should be the top left graph where there is point (1,1) and (-1, -1) y = 1/x
Step-by-step explanation:
from the original graph, I see:
f(x) = 2/x because f(2) = 1 = 2/2
f(1/4)= 2/(1/4) = 2
...
so then f(2x) compresses f(x) horizontally by a factor of 2
so f(2x) = 2/(2x) = 1/x
