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ruslelena [56]
3 years ago
12

Natalie Jenny, Steve and Jatin paid $12 for their taxi. They shared this equally between them. What fraction did each pay?

Mathematics
2 answers:
algol [13]3 years ago
8 0

Answer:

1/4

Step-by-step explanation:

12/4= 3

Each paid $3 but as a fraction 3/12=1/4

Fittoniya [83]3 years ago
3 0

Answer:

\frac{1}{4}

Step-by-step

12÷4=3

3/12=1/4-each pay this fraction

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2m+10=5m+100 what is the value of m
Morgarella [4.7K]

Answer:

m=-30

Step-by-step explanation:

2m+10=5m+100

get rid of 2m by subtracting

10=3m+100

get rid of 100 by subtracting

-90=3m

divide by 3

-30=m

m=-30

6 0
3 years ago
Your soccer team has won 6 games and lost 4 games. If the team does not lose any more games, how many games must the team win to
Lunna [17]

Answer: 4 games

Step-by-step explanation:

The team has won 6 games and lost 4 games. The win--loss ratio at the moment must be:

= 6 : 4

This must be at its simplest form which is:

= 3 :  2

To take it to 5 : 2, we would have to take up the left side of the ratio by 2.

Because we simplified by using a factor of 2, we have to multiply the 2 we just calculated by the factor to find the number of games needed to be won:

= 2 * 2

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4 0
3 years ago
The product of 8 and four more than a number<br> The algebraic expression is:
katovenus [111]

Answer:

8(n+4)

Step-by-step explanation:

4 0
3 years ago
The endpoints of JK are J(–5, 1) and K(7, –5). What are the coordinates of point P on JK that is the distance from point J to po
Andru [333]

Answer:

Step-by-step explanation:

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5 0
3 years ago
1. Let a be a positive real number. In Part (1) of Theorem 3.25, we proved that for each real number x, jxj &lt; a if and only i
krek1111 [17]

Answer:

(a)

if x \geq 0 then  x \geq a and if x<0 then -x > a

(b)

That is straightforward from what you showed on theorem 3.25

(c)

Following the same ideas from (a) x>a or -x > a.

Step-by-step explanation:

Remember how we define the absolute value of a number.

(a)

In general

|x| = x  \,\,\,\text{if}  \,\,\,\, x \geq 0 \\|x| = -x  \,\,\,\text{if}  \,\,\,\, x < 0

Therefore if |x| \geq a   you have two cases, if x \geq 0 then  x \geq a and if x<0 then -x > a

(b)

That is straightforward from what you showed on theorem 3.25

(c)

Following the same ideas from (a) x>a or -x > a.

8 0
3 years ago
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