If the baker made 5 pounds of icing and used 4/9 of the icing to make decorations, then he used:
5 * 4/9 =
= 20/9 =
= 2 2/9 [of icing]
To find out how much he has left over, we just need to substract 2 2/9 from 5:
5 - 2 2/9 =
= 3 - 2/9 =
= 2 7/9
Answer: The baker has <u>2 7/9</u> of the icing left.
Answer:
6, 2, 2/3, 2/9, 2/27, 2/81
Step-by-step explanation:
The nth term of a geometric progression is expressed as;
Tn = ar^n-1
a is the first term
n is the number of terms
r is the common ratio
Given
a = 6
r = 1/3
when n = 1
T1 = 6(1/3)^1-1
T1 = 6(1/3)^0
T1 = 6
when n = 2
T2= 6(1/3)^2-1
T2= 6(1/3)^1
T2 = 2
when n = 3
T3 = 6(1/3)^3-1
T3= 6(1/3)^2
T3= 6 * 1/9
T3 = 2/3
when n = 4
T4 = 6(1/3)^4-1
T4= 6(1/3)^3
T4= 6 * 1/27
T4 = 2/9
when n = 5
T5 = 6(1/3)^5-1
T5= 6(1/3)^4
T5= 6 * 1/81
T5 = 2/27
when n = 6
T6 = 6(1/3)^6-1
T6= 6(1/3)^5
T6= 6 * 1/243
T6 = 2/81
Hence the first six terms are 6, 2, 2/3, 2/9, 2/27, 2/81
Answer:
A= 66.6667
B = 333.3333
Step-by-step explanation:
Initial value of A = $20
Initial value of B = $80
Initial total=$ 28000
A moves up 50%= 20+(0.5*20)
A moves up 50% = 20+10
A moves up 50% =$ 30
B double it values = $80*2
B double it values = $160
Now total value is = $54000
A20+B80= 28000... equation 1
A30+B160= 54000.... equation 2
Multiplying equation 1 * 2
Multiplying equation 2 * 1
A40 +B160 = 56000
A30+B160= 54000
A30 = 2000
A= 2000/30
A= 200/3
A= 66.6667
A20+B80= 28000
Substituting A
200/3 (20) +B80= 28000
B80= 28000-4000/3
B80= 80000/3
B= 80000/240
B = 333.3333
9514 1404 393
Answer:
5 1/16 ft
Step-by-step explanation:
h(t) = -16t(t -18/16) . . . . put in intercept form
The function describes a parabola that opens downward. It has zeros at t=0 and t=9/8. The maximum height will be found at the vertex of the parabola, halfway between these zeros.
f(9/16) = (-16)(9/16)² +18(9/16) = 81/16 = 5 1/16 . . . . feet
The approximate maximum height of the leopard is 5 1/16 feet.
Answer:
g=6
Step-by-step explanation:
