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IRISSAK [1]
3 years ago
12

The ordered pairs (t, 36), (5, 45) represent a proportional relationship. Find the value of t.

Mathematics
2 answers:
olasank [31]3 years ago
6 0
The answer for t is 4 and the proportional relationship is 9
Paha777 [63]3 years ago
5 0
The value is 4 I hope this helped
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Please Help. &gt;.&lt;<br><br> Is This True Or False?
Viktor [21]

Answer:

False

Step-by-step explanation

I believe it's false

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3 years ago
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PLEASE SOLVE! Also how do you properly solve them ( please include steps)
Marizza181 [45]
1) 2x+3 = 5
-3 -3
2x =2
x=1

2) -x + 8 = 5
-8 -8
-x = -3
X=3


6 0
2 years ago
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Twenty four over the quantity of 3 x minus two. Find f(−2).
TEA [102]
Answer:

f(-2) = -3

Explanation:

Not sure if those last couple numbers are answer choices, but I'm going to infer that they might be.

Twenty four over the quantity of 3 x minus two in standard form is:

f(x) = <span>24<span>3x−2</span></span>

Since the number in the ( ) = x, plug in for x using f(-2)

<span>24<span>3∗<span>(−2)</span>−2</span></span>

P E {M D} {A S} for where to solve first

Multiply the 3 and (-2):

<span>24<span>−6−2</span></span>

Add -6 and -2:

<span>24<span>−8</span></span>

Divide the rest:

f(-2) = -3

3 0
3 years ago
Jennifer, Luis, Robert, Anna, and Tonya are figuring out how to split the check for lunch.
kramer

8 + 15 = 23

23 - 65.45 = 42.46.

The rest of the people in the group split $42 and 46 cents.

Hope this helped!!

6 0
3 years ago
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Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form of q(x)+r(x)/b(x)
natima [27]

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}

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(x^3+10x^2+13x+39)-(x^3+2x^2+x)=8x^2+12x+39

8x^2=8\cdot x^2, and 8(x^2+2x+1)=8x^2+16x+8. Subtracting this from the previous remainder gives a new remainder of

(8x^2+12x+39)-(8x^2+16x+8)=-4x+31

-84x is not a multiple of x^2, so we're done. Then

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=x+8+\dfrac{-4x+31}{x^2+2x+1}

4 0
3 years ago
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