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Alinara [238K]
3 years ago
8

THIS IS SUPER EASY I NEED HELP

Mathematics
2 answers:
charle [14.2K]3 years ago
6 0
\left(\dfrac{1}{2}\right)^5=\dfrac{1^5}{2^5}=\dfrac{1}{32}

2^5=2\cdot2\cdot2\cdot2\cdot2=32

Answer: \left(\dfrac{1}{2}\right)^5=\dfrac{1}{32}
Diano4ka-milaya [45]3 years ago
3 0
(1/2)^5 is equivalent to 

(1/2) x (1/2) x (1/2) x (1/2) x (1/2)

The answer is .<span>03125 or 1/32</span>
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Step-by-step explanation:

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3 years ago
Assume the sample below is a perfectly random sample of students at a school. How much greater is the mean of the
igor_vitrenko [27]

Answer:

0.75

Step-by-step explanation:

The table is not well presented (See Attachment)

There are at least two approaches to this question

Method 1:  

Steps

1. Calculate the mean of reported heights

Mean of reported heights = (61+68+57.5+48.5+75+65+80+68+69+63)/10

Mean of reported heights = 655/10

Mean of reported heights = 65.5

2. Calculate the mean of measured heights

Mean of measured heights = (62 + 68 + 56.5 + 47 + 72 + 65 + 78 + 67 + 69.5 + 62.5)/10

Mean of measured heights = 647.5/10

Mean of measured heights = 64.75

3. Get their difference

Difference = Mean of reported heights - Mean of measured heights

Difference = 65.5 - 64.75

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Method 2: Calculate the mean of their difference

Mean of difference = Sum of difference / Number of observations

Mean of difference = (-1 + 0 + 1 + 1.5 + 3 + 0 + 2 + 1 – 0.5 + 0.5)/10

Mean of difference = 7.5/10

Mean of difference = 0.75

Note that in both cases, the result is 0,75.

Hence, the reported heights at the school is 0.75 greater than the actual measured height

3 0
3 years ago
Read 2 more answers
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So the answer is C. y=9
5 0
2 years ago
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