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Rudiy27
3 years ago
7

A square matrix A is said to be idempotent iff A2 = A. (i) Show that if A is idempotent, then so is I − A. (ii) Show that if A i

s idempotent, then the matrix 2A − I is also invertible. Hint: Same as before, guess the inverse and check your answer with the definition of inverse.
Mathematics
1 answer:
muminat3 years ago
7 0

Answer:

Step-by-step explanation:

Given that A is a square matrix and A is idempotent

A^2 = A

Consider I-A

i) (I-A)^2 = (I-A).(I-A)\\= I^2 -2A.I+A^2\\= I-2A+A\\=I-A

It follows that I-A is also idempotent

ii) Consider the matrix 2A-I

(2A-I).(2A-I)=\\4A^2-4AI+I^2\\= 4A-4A+I\\=I

So it follows that 2A-I matrix is its own inverse.

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Consider a value to be significantly low if its z score less than or equal to minus−2 or consider a value to be significantly hi
katrin2010 [14]

Answer:

Test scores of 10.2 or lower are significantly low.

Test scores of 31.4 or higher are significantly high.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 20.8, \sigma = 5.3

Identify the test scores that are significantly low or significantly high.

Significantly low

Z = -2 and lower.

So the significantly low scores are thoses values that are lower or equal than X when Z = -2. So

Z = \frac{X - \mu}{\sigma}

-2 = \frac{X - 20.8}{5.3}

X - 20.8 = -2*5.3

X = 10.2

Test scores of 10.2 or lower are significantly low.

Significantly high

Z = 2 and higher.

So the significantly high scores are thoses values that are higherr or equal than X when Z = 2. So

Z = \frac{X - \mu}{\sigma}

2 = \frac{X - 20.8}{5.3}

X - 20.8 = 2*5.3

X = 31.4

Test scores of 31.4 or higher are significantly high.

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

12^2 + 5^2 = c^2

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Answer:

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Step-by-step explanation:

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Step-by-step explanation:

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